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Makovka662 [10]
3 years ago
12

Solve for the variables?

Mathematics
1 answer:
Ahat [919]3 years ago
3 0
We know that
cos 60°=1/2
cos 30°=(√3)/2
so
cos 60°=x/14---------> x=14*cos 60°----> x=14*(1/2)-----X=7 units
and
cos 30°=y/14---------> y=14*cos 30°----> x=14*(√3)/2----> y=7√3 units

the answers are
x=7 units
y=7√3 units

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An engineer wishes to determine the width of a particular electronic component. If she knows that the standard deviation is 1.6
nexus9112 [7]

Answer:

n=1705

Step-by-step explanation:

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Assuming the X follows a normal distribution  

X \sim N(\mu, \sigma=1.6)  

And the distribution for \bar X is:

\bar X \sim N(\mu, \frac{1.6}{\sqrt{n}})  

We know that the margin of error for a confidence interval is given by:  

Me=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)  

The next step would be find the value of \z_{\alpha/2}, \alpha=1-0.99=0.01 and \alpha/2=0.005  

Using the normal standard table, excel or a calculator we see that:  

z_{\alpha/2}=\pm 2.58  

If we solve for n from formula (1) we got:  

\sqrt{n}=\frac{z_{\alpha/2} \sigma}{Me}  

n=(\frac{z_{\alpha/2} \sigma}{Me})^2  

And we have everything to replace into the formula:  

n=(\frac{2.58(1.6)}{0.1})^2 =1704.03  

And if we round up the answer we see that the value of n to ensure the margin of error required \pm=0.1 mm is n=1705.  

6 0
3 years ago
A photographer made a 5-inch by 8-inch print of a photo. He then made a 10-inch by 16-inch print of the same photo. Which scale
GREYUIT [131]

Answer:

A.

Step-by-step explanation:

5x8 enlarged to 10x16

10 is 5x2 and 16 is 8x2

7 0
3 years ago
Please help me !!!! ill give brainly
NikAS [45]

Answer:

The answer is choices A.

Solutions:

m - 6 1/4 = 9 3/8

-3 1/8 - 6 1/4 = 9 3/8

7 0
3 years ago
According to a study done by De Anza students, the height for Asian adult males is normally distributed with an average of 66 in
Zolol [24]

Answer:

The probability that the person is between 65 and 69 inches is 0.5403

Step-by-step explanation:

Mean height = \mu = 66

Standard deviation = \sigma = 2.5

We are supposed to find What is the probability that the person is between 65 and 69 inches i.e.P(65<x<69)

Z=\frac{x-\mu}{\sigma}

At x = 65

Z=\frac{65-66}{2.5}

Z=-0.4

Refer the z table for p value

P(x<65)=0.3446

At x = 69

Z=\frac{69-66}{2.5}

Z=1.2

P(x<69)=0.8849

So,P(65<x<69)=P(x<69)-P(x<65)=0.8849-0.3446=0.5403

Hence the probability that the person is between 65 and 69 inches is 0.5403

6 0
3 years ago
Convert y - 1 = 2(x - 4)
Dimas [21]
The answer is y=2x-7
6 0
3 years ago
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