Can someone answer this for me?

Mathematics

1 answer:

andrey2020 [161]4 years ago

8 0

Answer:

19 x d = weekly pay

Step-by-step explanation:

6 + 2.5 + 3 + 4.5 + 3 = 19

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Here's another Math one worth 10.

tia_tia [17]

<span>In a 30-60-90 triangle the side opposite the 30 degree angle is half the length of the hypotenuse.
The short leg is </span>the side opposite the 30 degree angle. If the short leg =x, then the hypotenuse = 2x

The ratio of the short leg to the hypotenuse in the given triangle is cos(60°)

$
cos(60^o) = \frac{adjacent \ side}{hypotenuse } = \frac{x}{2x} = \frac{1}{2}$

Answer is C. 1:2

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3 years ago

The area of a trapezoid is 144 square inches. if the height is 12 inches, find the length of the median.

deff fn [24]

Answer: 12 inches

Step-by-step explanation: In this problem, since we're asked to find the length of the median, let's use our formula for the area of a trapezoid that involves the median which is shown below.

Area = median · height

We know that the area is 144 and the height is 9 so we can set up the equation 144 = M · 12. Now to solve for <em>m</em>, we divide both sides of the equation by 12 and we find that 12 = M.

So the length of the median of the trapezoid is 12 inches.

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3 years ago

Joe's Hot Dog Stand is only open for lunch. Of today's sales, 26% came from selling plain hot dogs. Since the hot dog stand made

fredd [130]

The answer to this question is $11.83

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3 years ago

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The cost of a pair of pants was reduced from $50 to $40. By what percent did the cost of the pair of pants decrease? 2% 10% 20%

vova2212 [387]

Answer:

C. 20%

Step-by-step explanation:

50*2=100

40*2=80

100-80=20

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3 years ago

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What is the simplified form of the expression k^3(K^7/5)^-5

Vladimir79 [104]

$\bf k^3\left( \cfrac{k^7}{5} \right)^{-5}\implies k^3\left( \cfrac{5}{k^7} \right)^5\implies k^3\left( \cfrac{5^5}{k^{7\cdot 5}} \right)\implies k^3\cdot \cfrac{5^5}{k^{35}}
\\\\\\
k^3\cdot 5^5\cdot k^{-35}\implies 5^5\cdot k^{3-35}\implies 5^5k^{-32}\implies \cfrac{5^5}{k^{32}}\implies \cfrac{3125}{k^{32}}$

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4 years ago