Please give information how u found the answer

Please help me find the surface area:)

Vlad1618 [11]

Answer:

48 im 100 percent sure

7 0

3 years ago

Read 2 more answers

company with a large fleet of cars hopes to keep gasoline costs down and sets a goal of attaining a fleet average of at least 26

podryga [215]

Answer:

$t=\frac{25.02-26}{\frac{4.83}{\sqrt{50}}}=-1.435$

$p_v =P(t_{(49)}$

If we compare the p value and the significance level assumed $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the height of men actually its significant lower than 26 so then the specification is satisfied.

Step-by-step explanation:

Data given and notation

$\bar X=25.02$ represent the sample mean

$s=4.83$ represent the sample standard deviation

$n=50$ sample size

$\mu_o =26$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is at least 26 mpg, the system of hypothesis would be:

Null hypothesis: $\mu \geq 26$

Alternative hypothesis: $\mu < 26$

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{25.02-26}{\frac{4.83}{\sqrt{50}}}=-1.435$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=50-1=49$

Since is a one sided test the p value would be:

$p_v =P(t_{(49)}$

Conclusion

If we compare the p value and the significance level assumed $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the height of men actually its significant lower than 26 so then the specification is satisfied.

3 0

3 years ago

The 100-meter dash times in the girls track meet were normally distributed with a mean of 13 seconds and a standard deviation of

WITCHER [35]

Answer:

The probability is 0.97682

Step-by-step explanation:

We start by finding the z-values of the runner times given.

Mathematically;

z-score = (x-mean)/SD

From the question, mean = 13 seconds and SD = 0.3 seconds

So for 12.4 seconds, we have;

z = (12.4-13)/0.3 = -0.6/0.3 = -2

For 14 seconds, we have;

z = (14-13)/0.3= 1/0.3 = 3.33

So the probability we want to calculate is;

P(-2<z<3.33)

We can find this using the standard normal distribution table

Mathematically;

P(-2<z<3.33) = P(z<3.33) - P(z < -2)

Using the standard normal distribution table, the value of this is;

P(-2<z<3.33) = 0.97682

7 0

3 years ago

Evaluate all of these for the code

Marat540 [252]

Answer:

7816

BHID is your code

Step-by-step explanation:

1. 7

3b+a²

3(2)+1²

6+1

7

2. 8

4(e - c)

4(5-3)

4(2)

8

3. 1

2e-3c

2(5)-3(3)

10-9

1

4. 6

e+a-3f

5+1-3(0)

5+1

6

6 0

3 years ago

Which of these would be an appropriate method to show a quadrilateral is a rectangle?

Serhud [2]

Answer:

Use the distance formula six times to show that the opposite sides and the diagonals are congruent

Step-by-step explanation:

A polygon is a two-dimensional shape formed using straight lines. A rectangle is a four-sided polygon in which all the interior angles are right angles.

Also, the opposite sides of the rectangle are parallel and of equal length.

Both diagonals of a rectangle are also congruent.

A rectangle is a quadrilateral in which opposite sides and the diagonals are congruent.

5 0

4 years ago