All categories

3 years ago

You borrow $3,897 for a loan for college expenses with a 2.5% interest rate. How much interest is charged on the loan

Mathematics

1 answer:

belka [17]3 years ago

7 0

Answer:

Amount of interest pay per year = $97.5 (Approx.)

Step-by-step explanation:

Given:

Amount borrow for college expenses = $3,897

Rate of interest = 2.5%

Find:

Amount of interest pay per year

Computation:

Using Simple interest formula;

Simple interest = Amount borrow x Rate of interest x number of year

Amount of interest pay per year = 3,897 x 2.5% x 1

Amount of interest pay per year = 3,897 x 0.025

Amount of interest pay per year = 97.425

Amount of interest pay per year = $97.5 (Approx.)

You might be interested in

A new vending machine costs $4,500.00 and it is on sale for 10%. What is the price of the vending machine after the discount is

dlinn [17]

Answer: Probably $4,050

Step-by-step explanation:

The way you worded this is weird but I’m assuming you meant 10% off. Find 10% of 4500 (which is 450) and subtract that from the total, giving you 4050.

3 0

3 years ago

Which of the following scatterplots represents the data shown below?

AleksAgata [21]

Answer:

Step-by-step explanation:

4 0

4 years ago

Can y’all help me me on question 2?! Have a good day!

AfilCa [17]

Answer:

Step-by-step explanation:

The formula to get the area of a triangle is A= $\frac{(b)(h)}{2}$ so all you have to do is work backwards. 18x2=36. 36/4=9.

6 0

3 years ago

I. B=C

olga55 [171]

Answer:

B.) I, II, and III

Step-by-step explanation:

They are all congruent.

7 0

3 years ago

Examination, 152 Candidates offered Agriculture

agasfer [191]

SOLUTION

Given the question in the image, the following are the solution steps to answer the question

STEP 1: Write the given details

$n(G)=136,n(P)=128,n(A)=152,n(A\cap G)=52,n(A\cap P)=60,n(A\cap P\cap G)=30,n(P\cap G)=58$

STEP 2: Get the number of students that takes the subjects only

From the basic stuff, we have Number of candidates who had taken only each of the subjects

$\begin{gathered} n(A\text{ only)=}n(A)-\lbrack n(A\cap P)+n(A\cap G)-n(A\cap P\cap G)_{}\rbrack \\ \Rightarrow152-\lbrack52+60-30\rbrack=152-82=70 \\ \\ n(G\text{ only)=}n(G)-\lbrack n(A\cap G)+n(P\cap G)-n(A\cap P\cap G)\rbrack \\ \Rightarrow136-\lbrack52+58-30\rbrack=56 \\ \\ n(P\text{ only)=}128-\lbrack58+60-30\rbrack=40 \end{gathered}$

STEP 3: Represent the values above on a Venn Diagram after getting the values

STEP 4: Find the total number of candidate that sat for the exam.

$\begin{gathered} We\text{ su}m\text{ all the numbers in the Venn diagram to get the total number of candidates that sat for the exam} \\ We\text{ have:} \\ 70+22+30+30+28+56+40=276 \end{gathered}$

Hence, the total number of candidates that sat for the exam is 276

5 0

1 year ago

Read 2 more answers