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3 years ago

The circumference of a tire is 31.4 inches. What is the radius of the tire? HELPPPPPPPPPPPPPPPPPPPPPPPPP

Mathematics

1 answer:

LuckyWell [14K]3 years ago

6 0

Answer:

Step-by-step explanation:

circumference of the circle, C=2*3.14*r

C=31.4

31.4=2*3.14*r

r=31.4/(2*3.14)=5

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Plz Answer

motikmotik

(0-0)÷(-3-5)=0
it is zero

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3 years ago

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Question 6(Multiple Choice Worth 1 points) (02.05 MC) Choose the table that represents g(x) = 4⋅f(x) when f(x) = x − 5. x g(x) 1

RSB [31]

Answer: (b)

x g(x)

1 -16

2 -12

3 -8

If g(x) is 4*f(x), then we can find g(x) by multiplying 4 by x-5

g(x) = 4(x-5)

= 4x-20

Now we can plug in 1,2, and 3 for x to see which table makes sense.

g(1) = 4(1) - 20

= -16

g(2) = 4(2) - 20

= -12

g(3) = 4(3) - 20

= -8

hope this helps

4 0

3 years ago

Please solve will give brainliest

alina1380 [7]

$1 \times \frac{5}{8}$

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3 years ago

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Y=-2<br><img src="https://tex.z-dn.net/?f=y%20%3D%20%20-%202%20%5C%5C%204x%20-%203y%20%3D%2018" id="TexFormula1" title="y = - 2

Morgarella [4.7K]

I think is
4x - 3 (-2) = 18
4x + 6 = 18
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5 0

3 years ago

Find the particular solution of the differential equation that satisfies the initial condition(s). f ''(x) = x−3/2, f '(4) = 1,

sweet [91]

Answer:

Hence, the particular solution of the differential equation is $y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x$ .

Step-by-step explanation:

This differential equation has separable variable and can be solved by integration. First derivative is now obtained:

$f'' = x - \frac{3}{2}$

$f' = \int {\left(x-\frac{3}{2}\right) } \, dx$

$f' = \int {x} \, dx -\frac{3}{2}\int \, dx$

$f' = \frac{1}{2}\cdot x^{2} - \frac{3}{2}\cdot x + C$ , where C is the integration constant.

The integration constant can be found by using the initial condition for the first derivative ( $f'(4) = 1$ ):

$1 = \frac{1}{2}\cdot 4^{2} - \frac{3}{2}\cdot (4) + C$

$C = 1 - \frac{1}{2}\cdot 4^{2} + \frac{3}{2}\cdot (4)$

$C = -1$

The first derivative is $y' = \frac{1}{2}\cdot x^{2}- \frac{3}{2}\cdot x - 1$ , and the particular solution is found by integrating one more time and using the initial condition ( $f(0) = 0$ ):

$y = \int {\left(\frac{1}{2}\cdot x^{2}-\frac{3}{2}\cdot x -1 \right)} \, dx$

$y = \frac{1}{2}\int {x^{2}} \, dx - \frac{3}{2}\int {x} \, dx - \int \, dx$

$y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x + C$

$C = 0 - \frac{1}{6}\cdot 0^{3} + \frac{3}{4}\cdot 0^{2} + 0$

$C = 0$

Hence, the particular solution of the differential equation is $y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x$ .

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3 years ago