Answer:
Bottom right. It's correct
complete question:
The sum of the digits of a two-digit numeral is 8. If the digits are reversed, the new number is 18 greater than the original number. How do you find the original numeral?
Answer:
The original number is 10a + b = 10 × 3 + 5 = 35
Step-by-step explanation:
Let
the number = ab
a occupies the tens place while b occupies the unit place. Therefore,
10a + b
The sum of the digits of two-digits numeral
a + b = 8..........(i)
If the digits are reversed. The reverse digit will be 10b + a. The new number is 18 greater than the original number.
Therefore,
10b + a = 18 + 10a + b
10b - b + a - 10a = 18
9b - 9a = 18
divide both sides by 9
b - a = 2...............(ii)
a + b = 8..........(i)
b - a = 2...............(ii)
b = 2 + a from equation (ii)
Insert the value of b in equation (i)
a + (2 + a) = 8
2a + 2 = 8
2a = 6
a = 6/2
a = 3
Insert the value of a in equation(ii)
b - 3 = 2
b = 2 + 3
b = 5
The original number is 10a + b = 10 × 3 + 5 = 35
Answer:
I'm pretty sure It's 2172.20 (I may be wrong It's been a while since I did this)
Step-by-step explanation:
Triangle Area = .5 * base * height
48 = .5 * (x +4) * x
48 = (.5x + 2) * x
48 = .5x^2 + 2x
.5x^2 + 2x -48 = 0
x = 8
base = 12
-7=z/2+1
What you first need to do is to multiply both sides of the equation by 2
-14=z+2
Now you move the variable to the left side and change within it’s own sign
-z-14=2
Into
-z=2+14
Now you then add the numbers
-z=16
The last part you do is change the sign on both sides in this equation
z=-16
Therefore, z=-16 is your answer in number 16.
