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lbvjy [14]
3 years ago
15

Help please need help ASAP

Mathematics
1 answer:
Elanso [62]3 years ago
3 0

Answer:

g phone the other questions please let me that he had an amazing time to Suna tha wo boli kya mama I have a doctor and square footage clip for more details on Friday November this year and square footage clip and square footage of rectangular shape or comments regarding the questions that may arise in touch as soon I have received a sum of Plassey and sahi h jo the questions I had to the best of Plassey the questions. Aladdin Nam to Suna he hoga

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PLEASE HELP!!!!!!!!
Elanso [62]

Answer:

i think its x

Step-by-step explanation:

6 0
4 years ago
Write an equation for the line that passes through the points (4, 8) and (6, 2).
dybincka [34]

Answer:

y

Step-by-step explanation:

Just use the formula...,

; y - y(coordinate) = slope × [ x - x(coordinate)]

; where we firstly have to calculate the slope...,

; (8 - 2)/(4 - 6) = -3

Then substitute into the formula using point(4, 8)...and you can also use the other point if you wish to

; y - 8 = (-3)(x - 4)

; y - 8 = -3x + 12

Hence the equation of the line....,

; y = -3x + 20

3 0
3 years ago
Need help quick please
valina [46]

Answer:

Disagree

Step-by-step explanation:

Remember rotating 90 degrees  means (y,-x)

A= (1,2)

A'= (2,-1)

So it is disagreed.

Hope this help :)

3 0
3 years ago
Read 2 more answers
If they were part of the same expression, which of the following would be considered like terms with the given monomial?
dedylja [7]

Answer: OPTION B

Step-by-step explanation:

The like term of the given monomial 5m^2n must have the following characteristics:

- The exponent of "m" must be "2".

- The exponent of "n" must be "1".

Then, you can observe that the option that shows a monomial with this characteristics is the option B.

Therefore, the like term with the given monomial 5m^2n is:

-m^2n

7 0
3 years ago
How would you write the following expression as a single term? 3[2 ln(x-1) - lnx] + ln (x+1)
Elan Coil [88]

Apply the rule: n ln x = ln x^{n}

3[2 ln(x-1) - lnx] + ln(x+1)=3[ln(x-1)^{2} - lnx ] + ln(x+1)

Apply the rule : log a - log b = log \frac{a}{b}

3[2 ln(x-1) - lnx] + ln(x+1)=3ln\frac{(x-1)^{2} }{x} + ln(x+1)

Apply the rule: n ln x = ln x^{n}

3[ln (x-1)^{2} -ln x]+ln (x+1)= ln \frac{(x-1)^{6} }{x^{3} } +log(x+1)

Finally, apply the rule: log a + log b = log ab

3[ln(x-1)^{2} -ln x]+log(x+1)=ln\frac{(x-1)^{6}(x+1) }{x^{3} }

3 0
4 years ago
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