1/6 of the people are not elderly or men
<h3>How to determine the proportion?</h3>
The given parameters are:
Men = 1/2
Elderly = 1/3
The number of people that are not elderly or men are:
People = 1 - Men - Elderly
So, we have:
People = 1 - 1/2 - 1/3
Evaluate
People = 1/6
Hence, 1/6 of the people are not elderly or men
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Answer:
Step-by-step explanation:
You need to change the denominator into a the least common denominator, 4 and 3 both have 12 in common. 12 is your new denominator but what you to the bottom you must do to the top. So when you multiply 3/4 by 3/3 you will get 9/12.
Then you want to make 4 1/3 into a improper fraction, which would be 13/3 you want to multiply this by 4 and you will get 52/12. You will then add 52/12 to 9/12 and get 61/12 or 5 1/12.
If you need any more help please let me know.
Answer:
∠1 ≅ ∠2 ⇒ proved down
Step-by-step explanation:
#12
In the given figure
∵ LJ // WK
∵ LP is a transversal
∵ ∠1 and ∠KWP are corresponding angles
∵ The corresponding angles are equal in measures
∴ m∠1 = m∠KWP
∴ ∠1 ≅ ∠KWP ⇒ (1)
∵ WK // AP
∵ WP is a transversal
∵ ∠KWP and ∠WPA are interior alternate angles
∵ The interior alternate angles are equal in measures
∴ m∠KWP = m∠WPA
∴ ∠KWP ≅ ∠WPA ⇒ (2)
→ From (1) and (2)
∵ ∠1 and ∠WPA are congruent to ∠KWP
∴ ∠1 and ∠WPA are congruent
∴ ∠1 ≅ ∠WPA ⇒ (3)
∵ WP // AG
∵ AP is a transversal
∵ ∠WPA and ∠2 are interior alternate angles
∵ The interior alternate angles are equal in measures
∴ m∠WPA = m∠2
∴ ∠WPA ≅ ∠2 ⇒ (4)
→ From (3) and (4)
∵ ∠1 and ∠2 are congruent to ∠WPA
∴ ∠1 and ∠2 are congruent
∴ ∠1 ≅ ∠2 ⇒ proved
It is not factorable. Factors of 21 are. 21 and 1
7 and 3. None of those add up to 12
