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murzikaleks [220]
3 years ago
7

The area of the rectangle is 40% larger than the area of the triangle.What is the length ,L, of the rectangle?

Mathematics
1 answer:
Nezavi [6.7K]3 years ago
3 0

Answer:

10 units

Step-by-step explanation:

Area of the triangle (A') = 1/2bh

A' = 1/2bh............ Equation 1

Where b = base of the triangle, h = height of the triangle

From the diagram,

Given: b = 12.5 unit, h = 4 unit

Substitute into equation 1

A' = 1/2(12.5)(4)

A' = 25 squared unit.

Also,

Area of the rectangle (A) = Lenght(L)×width(w)

A = Lw............ Equation 2

From the question,

If the area of the rectangle is 40% larger than the area of the triangle

Therefore,

A = 1.4A'

A = 1.4(25)

A = 35 squared unit.

Also given: w = 3\frac{1}{2} = 7/2

Substitute into equation 2

35 = L×7/2

7L = 35×2

7L = 70

L = 70/7

L = 10 units

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The rectangle can be 12 ft by 16 ft. The longer dimension is 16 ft.

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How many terms are in the expression 5x+3y-2z​
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Step-by-step explanation:

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Is the relation in this set of points a function
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7 0
2 years ago
The length of a rectangle is shown below: On a coordinate grid from negative 6 to positive 6 on the x-axis and on the y-axis two
Degger [83]

9514 1404 393

Answer:

  3.  C(−1, −5), D(2, −5)

Step-by-step explanation:

The given points are 2 -(-1) = 3 units apart horizontally, so the remaining points will need to be 18/3 = 6 units below, vertically. Translating the given points down 6 gives ...

  D = A -(0, 6) = (2, 1) -(0, 6) = (2, -5)

  C = B -(0, 6) = (-1, 1) -(0, 6) = (-1, -5)

The two points required to make a rectangle with an area of 18 square units are ...

  C(-1, -5), D(2, -5)

_____

The area of a rectangle is the product of length and width. If the area is 18 square units, and the width is 3 units, then the length must be 6 units. 3×6=18.

5 0
2 years ago
Please help with this arc equation.
boyakko [2]

Answer:

Part 1) arc\ AB=49^o

Part 2) arc\ ABC=204^o

Part 3) arc\ BAC=156^o

Part 4) arc\ ACB=311^o

Step-by-step explanation:

Part 1) Find the measure of arc AB

we know that

arc\ AB=m\angle AOB ----> by central angle

we have

m\angle AOB=49^o

therefore

arc\ AB=49^o

Part 2) Find the measure of arc ABC

we know that

The central angle of complete circle is equal to 360 degrees

so

arc\ ABC=360^o-107^o-49^o=204^o

Part 3) Find the measure of arc BAC

we know that

arc\ BAC=arc\ BA+arc\ AC ----> by angle addition postulate

we have

arc\ BA=49^o ---> by central angle

arc\ AC=107^o ---> by central angle

so

arc\ BAC=49^o+107^o=156^o

Part 4) Find the measure of arc ACB

we know that

The central angle of complete circle is equal to 360 degrees

so

arc\ ACB=360^o-arc\ AB

substitute

arc\ ACB=360^o-49^o=311^o

4 0
3 years ago
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