The area of the rectangle is 40% larger than the area of the triangle.What is the length ,L, of the rectangle?
1 answer:
Answer:
10 units
Step-by-step explanation:
Area of the triangle (A') = 1/2bh
A' = 1/2bh............ Equation 1
Where b = base of the triangle, h = height of the triangle
From the diagram,
Given: b = 12.5 unit, h = 4 unit
Substitute into equation 1
A' = 1/2(12.5)(4)
A' = 25 squared unit.
Also,
Area of the rectangle (A) = Lenght(L)×width(w)
A = Lw............ Equation 2
From the question,
If the area of the rectangle is 40% larger than the area of the triangle
Therefore,
A = 1.4A'
A = 1.4(25)
A = 35 squared unit.
Also given: w = 3 = 7/2
Substitute into equation 2
35 = L×7/2
7L = 35×2
7L = 70
L = 70/7
L = 10 units
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<u>Given</u>:
Given that the regular decagon has sides that are 8 cm long.
We need to determine the area of the regular decagon.
<u>Area of the regular decagon:</u>
The area of the regular decagon can be determined using the formula,
where s is the length of the side and n is the number of sides.
Substituting s = 8 and n = 10, we get;
Simplifying, we get;
Rounding off to the nearest whole number, we get;
Thus, the area of the regular decagon is 642 cm²
Hence, Option B is the correct answer.