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Alborosie
3 years ago
10

If 800g of a radioactive substance are present initially and 8 years later only 450g remain, how much of the substance will be p

resent after 16 years? (Round answer to a whole number)
Mathematics
1 answer:
artcher [175]3 years ago
5 0

A=Pe^(rt)

P = 800g

t = 8 years

A = 450g

r = This is what we will try and find to start with

450=800e^(r*8)

After running the math through a calculator, we end with r = -0.07192

Now we just re-input this information into our equation: A=800e^(-0.07192*16)

A=800e^(1.15072)

Now we will re-write the equation using the negative exponent rule:

A = 800 1/e^1.15072

Combine right side:

A = 800/e^1.15072

Then do the math:

A = 253.12709836......

That will give us A = 253 (rounded to the whole number)

I hope this helps! :)

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Answer:

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Step-by-step explanation:

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Here is how I did it:

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Step-by-step explanation:

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Step-by-step explanation:

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plz....

mark it as a brilliant answer

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2 years ago
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