Answer:
Part 1) Slope-intercept form
Part 2) The slope of 2.20 tells me the rate per mile and the y-intercept of 2.50 tells me the flat fee
Step-by-step explanation:
Part 1) we know that
The linear equation in slope intercept form is equal to

where
m is the slope or unit rate
b is the y-intercept or initial value
In this problem we have

This is a linear equation in slope intercept form
where


Part 2) we have that
x -----> represent the number of miles
y ----> represent the total charge in dollars
The slope is
---> unit rate
The y-intercept is
----> initial value or flat fee
therefore
The slope of 2.20 tells me the rate per mile and the y-intercept of 2.50 tells me the flat fee
8+11=19 but if you add 21+19+12+5=57.
Answer: this dose not even make sense
Step-by-step explanation:
You only put a pdf
Answer:
From $1600 to $3400.
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviation of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean = 2500
Standard deviation = 300
What interval of dealer incentives would we expect approximately 99.7% of vehicles to fall within?
By the Empirical Rule, 99.7% fall within 3 standard deviations frow the mean. So
From 2500 - 3*300 = 1600 to 2500 + 3*300 = 3400.
The x- and y- coordinates of point P on the directed line segment from K to J such that P is Three-fifths the length of the line segment from K to J is (85, 105).
Given
On a coordinate plane, a line is drawn from point K to point J. Point K is at (160, 120) and point J is at (negative 40, 80).
<h3>Coordinates</h3>
The coordinates point any point can be found by using the following formula.

The x- and y- coordinates of point P on the directed line segment from K to J such that P is Three-fifths the length of the line segment from K to J is;

Hence, the x- and y- coordinates of point P on the directed line segment from K to J such that P is Three-fifths the length of the line segment from K to J is (85, 105).
To know more about co-ordinates click the link given below.
brainly.com/question/13847533