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Galina-37 [17]
3 years ago
14

Giving thanks and brainliest for best answer <3

Mathematics
1 answer:
Papessa [141]3 years ago
5 0
It’s definitely 100% B sorry if I’m late :)
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How do i solve x^2+7x=3x
valina [46]
To solve, you must make one side of the equation equal to zero. We can do this by subtracting 3x on both sides of the equation.

<span>x^2 + 7x = 3x
</span>       - 3x    -3x

x^2 + 4x = 0.

Then we substitute the equation into the quadratic equation.

\frac{-b+- \sqrt{b^2-4ac} }{2a}

Where a = 1 b = 4 and c = 0

\frac{-(4)+- \sqrt{(4)^2-4(1)(0)} }{2(1)}

We first solve whats inside the square root.

\frac{-(4)+- \sqrt{16} }{2(1)}

\sqrt{16} = 4

Now we solve for -4 and 4.

-4 - 4 = -8
-4+4=0

Then divide both answer by 2

\frac{-8}{2} = -4
The division of any by zero is zero

So the answer are x = -4 and x = 0
7 0
4 years ago
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What are the terms in the expression 7x+4y+1?
Vanyuwa [196]

Answer:

D.

x and y are the terms think about the letters in the expression and those are the terms.

4 0
3 years ago
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Find function domain <br> f(x) = sqrt( 2sin x - 1 )
vekshin1

Answer:

{x ∈ ℝ : x ≥ π/6 +2πn and x ≤ π/6 + 2πn and n ∈ ℤ}

Step-by-step explanation:

sinx can run from -1 to +1

2sinx can run from -2 to +2

2sinx -1 can run from -3 to +1

However, the square root is imaginary when x < 0. So, the condition is

2sinx -1 ≥ 0

2sinx ≥ 1

sinx ≥ ½

x ≥ π/6 (30°)

So, in the interval [0, 2π], π/6 ≤ x ≤ 5π/6

However, the sine is a cyclic function and repeats itself every 2π.

Over all real numbers, the condition is (π/6 +2πn) ≤ x ≤ (5π/6 + 2πn).

The domain is then

{x ∈ ℝ : x ≥ π/6 +2πn and x ≤ π/6 + 2πn and n ∈ ℤ}

5 0
3 years ago
What value of x makes this equation true -6x+3= 45
LiRa [457]
-6x+3=45
-3 -3 subtract
-6x=45
Divide both sides by -6
X=-7
I think this is the answer
6 0
3 years ago
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THIS IS ADVICE TO PPL WHO WANNA WATCH THAT MOVIE "MEGAN IS MISSING"
seropon [69]

Answer:

"Okay, I jotted it down on my handy dandy notepad"

     <em>- quoted by Blues clues and then used by Melissa Pirie in order to answer/take this girl/boy advice</em>

<u>also if possible can i have brainliest</u>

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