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castortr0y [4]
3 years ago
13

I NEED HELP PLEASE!!

Mathematics
1 answer:
Mrac [35]3 years ago
6 0

Answer:3.38

Step-by-step explanation:

Count, N: 5

Sum, Σx: 18

Mean, μ: 3.6

Variance, σ2:  11.44

Steps

(10 - 3.6)2 + ... + (2 - 3.6)2

5

=  

57.2

5

=  11.44

σ =  √11.44

=  3.38

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If you had 1052 toothpicks and were asked to group them in powers of 6, how many groups of each power of 6 would you have? Put t
sukhopar [10]

1052 toothpicks can be grouped into 4 groups of third power of 6 (6^{3}), 5 groups of second power of 6 (6^{2}), 1 group of first power of 6 (6^{1}) and 2 groups of zeroth power of 6 (6^{0}).

The number 1052, written as a base 6 number is 4512

Given: 1052 toothpicks

To do: The objective is to group the toothpicks in powers of 6 and to write the number 1052 as a base 6 number

First we note that, 6^{0}=1,6^{1}=6,6^{2}=36,6^{3}=216,6^{4}=1296

This implies that 6^{4} exceeds 1052 and thus the highest power of 6 that the toothpicks can be grouped into is 3.

Now, 6^{3}=216 and 216\times 5=1080, 216\times 4=864. This implies that 216\times 5 exceeds 1052 and thus there can be at most 4 groups of 6^{3}.

Then,

1052-4\times6^{3}

1052-4\times216

1052-864

188

So, after grouping the toothpicks into 4 groups of third power of 6, there are 188 toothpicks remaining.

Now, 6^{2}=36 and 36\times 5=180, 36\times 6=216. This implies that 36\times 6 exceeds 188 and thus there can be at most 5 groups of 6^{2}.

Then,

188-5\times6^{2}

188-5\times36

188-180

8

So, after grouping the remaining toothpicks into 5 groups of second power of 6, there are 8 toothpicks remaining.

Now, 6^{1}=6 and 6\times 1=6, 6\times 2=12. This implies that 6\times 2 exceeds 8 and thus there can be at most 1 group of 6^{1}.

Then,

8-1\times6^{1}

8-1\times6

8-6

2

So, after grouping the remaining toothpicks into 1 group of first power of 6, there are 2 toothpicks remaining.

Now, 6^{0}=1 and 1\times 2=2. This implies that the remaining toothpicks can be exactly grouped into 2 groups of zeroth power of 6.

This concludes the grouping.

Thus, it was obtained that 1052 toothpicks can be grouped into 4 groups of third power of 6 (6^{3}), 5 groups of second power of 6 (6^{2}), 1 group of first power of 6 (6^{1}) and 2 groups of zeroth power of 6 (6^{0}).

Then,

1052=4\times6^{3}+5\times6^{2}+1\times6^{1}+2\times6^{0}

So, the number 1052, written as a base 6 number is 4512.

Learn more about change of base of numbers here:

brainly.com/question/14291917

6 0
2 years ago
(12x6) - (3x2) how do you write in words to match the expression?
notka56 [123]

twelve multiplied by six equals seventy two. Three multiplied by two equals six. Therefore seventy-two plus six equals seventy-eight
7 0
3 years ago
The revenue for a vehicle rental store is $5460. There was 208 cars and 52 vans rented. A van rents for $10 more than a car.
Darya [45]
208c + 52v = 5460
v = c + 10

where c = the price for a car rental and v = the price for a van rental.
To solve this system, use substitution; the second equation says v is equal to c + 10, so plug in "c + 10" for v in the first equation and solve for c:

208c + 52(c + 10) = 5460
208c + 52c + 520 = 5460
260c + 520 = 5460
260c = 4940
c = 19

Now that we have c, we can plug it in to the second equation to find v:

v = (19) + 10
v = 29

So, c = 19 and v = 29, meaning that
The cost of a car rental is $19 and the cost of a van rental is $29.
7 0
3 years ago
I totally need helppppppppp. Oh no im gonna faillllllll.
brilliants [131]

Answer:

19 will be the answer.

Step-by-step explanation:

10+9=19

8 0
3 years ago
Read 2 more answers
The two shapes have the same area. Work out the perimeter of the rectangle.
elena-14-01-66 [18.8K]
You need to do this in several steps.

1) Using the given length and width of the rectangle, find its area.
2) Then using the base and height of the triangle, find its area.
3) Since the areas are equal, set the expressions equal to each other, and solve for x.
4) Using the value of x you found, find the length and width of the rectangle and find its perimeter.

1) The area of the rectangle is A = LW
Area of Rectangle = (x + 2)x = x^2 + 2x

2) The area of the triangle is A = (1/2)bh
Area of Triangle = (1/2)(24)x = 12x

3) Set the areas equal and solve for x

x^2 + 2x = 12x

x^2 - 10x = 0

x(x - 10) = 0

x = 0 or x = 10

Since a width cannot be 0, we discard x = 0, and keep x = 10.

4) The length is x + 2 = 10 + 2 = 12
The width is x = 10

The perimeter is 2(L + W) = 2(10 + 2) = 2(22) = 44

The perimeter is 44 cm.
4 0
3 years ago
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