Answer:
Question 1: how much more does 1 1/4 pounds of beef cost than 1 1/4 pounds of turkey?
$4.25/pound (beef) / 4 = $1.06 per 1/4 lb = $4.25 + $1.06 = $5.31 per 1 1/4 lb
$2.85/pound (turkey) / 4 = $0.71 per 1/4 lb = $2.85 + $0.71 = $3.56 per 1 1/4 lb
$5.31 - $3.56 = $1.75 the beef is more expensive by this much compared to the 1 1/4 lb of turkey
Question 2: question 2. brad has 10 dollars to spend at ruby's. He orders 1/2 pound of sausage and 1 1/4 pounds of chicken. How much money will he brad have after he pays for this order?
$3.25 / 2 = $1.62 per 1/2 pound of sausage
$2.50 / 4 = $0.62 per 1/4 lb of chicken + $2.50 = $3.13 per 1 1/4 lb of chicken
$1.62 (1/2 lb sausage) + $3.13 (1 1/4 lb chicken) =$4.75
$10 (budget) - $4.75 (total expense) = $5.25 Brad will have this left
The correct answer for the question that is being presented above is this one: "A. Division of skin cells every half hour; B. Small graph of y=x squared; C. y= 4 times 3 raised to x; D. y=2x raised to the 3." T<span>hese choices represent an exponential pattern.</span>
Answer:
A. 23+x=140
Step-by-step explanation:
The angle addition postulate states that the measure of a larger angle formed by two or more smaller angles placed side by side is the the sum of the smaller angles. The angle addition postulate states that if B is in the interior of AOC , then:
m∠AOB + m∠BOC = m∠AOC.
From the image:
∠NOP = ∠NOQ + ∠QOP
∠NOP = 140, ∠NOQ = x, ∠QOP = 23
substituting:
140 = x + 23
x = 140 - 23 = 117
∠NOQ = 117°
Answer:
b = 45.9 - c
Step-by-step explanation:
A scalene triangle has non of its sides equal.
Perimeter = 54.6
side a = 8.7 cm
side b = unknown
side c = unknown
Perimeter of a shape is sum of all its sides.
Perimeter = a + b + c
54.6 = 8.7 + b + c
Making b the subject
b = 54.6 - 8.7 - c
b = 45.9 - c
The value of b is (45.9 - c)
Answer:
a) 229 and 305 days
b) 229 days or less
c) 305 days or more
Step-by-step explanation:
The Empirical Rule(68-95-99.7 rule) states that, for a normally distributed random variable:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviation of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean = 267
Standard deviation = 19
(a) Between what values do the lengths of the middle 95% of all pregnancies fall?_____________and___________days
By the Empirical rule, 95% of all pregnancies fall within 2 standard deviations of the mean.
So
267 - 2*19 = 229 days
to
267 + 2*19 = 305 days
(b) How short are the shortest 2.5% of all pregnancies?______days or less
95% of all pregnancies fall within 2 standard deviations of the mean. The other 5% are more than 2 standard deviations from the mean. Since the distribution is symmetric, 2.5% is more than 2 standard deviations below the mean(shortest 2.5%) and 2.5% is more than 2 standard deviations above the mean(longest 2.5%). So
267 - 2*19 = 229 days
c) How long do the longest 2.5% of pregnancies last?________days or more
Explanation in b)
267 + 2*19 = 305 days
