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Pani-rosa [81]
4 years ago
11

A technician compares repair costs for two types of microwave ovens (type I and type II). He believes that the repair cost for t

ype I ovens is greater than the repair cost for type II ovens. A sample of 60 type I ovens has a mean repair cost of $⁢85.79, with a standard deviation of $⁢15.13. A sample of 56 type II ovens has a mean repair cost of $78.67, with a standard deviation of $⁢17.84. Conduct a hypothesis test of the technician's claim at the 0.1 level of significance. Let μ1 be the true mean repair cost for type I ovens and μ2 be the true mean repair cost for type II ovens.Step 1 of 4: State the null and alternative hypotheses for the test.Step 2 of 4: Compute the value of the test statistic. Round your answer to two decimal places.Step 3 of 4: Determine the decision rule for rejecting the null hypothesis H0. Round the numerical portion of your answer to three decimal places.Step 4 of 4: Make the decision for the hypothesis test. Reject or Fail to Reject Null Hypothesis
Mathematics
1 answer:
hoa [83]4 years ago
3 0

Answer:

Since p value <0.1 accept the claim that oven I repair costs are more

Step-by-step explanation:

The data given for two types of ovens are summarised below:

Group   Group One     Group Two  

Mean 85.7900 78.6700

SD 15.1300 17.8400

SEM 1.9533 2.3840

N 60       56      

Alpha = 10%

H_0: \mu_1 - \mu_2 =0\\H_a: \mu_1 - \mu_2> 0

(Right tailed test)

The mean of Group One minus Group Two equals 7.1200

df = 114

 standard error of difference = 3.065

 t = 2.3234

p value = 0.0219

If p value <0.10 reject null hypothesis

4) Since p value <0.1 accept the claim that oven I repair costs are more

 

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Hi,

y - 5 = -2(x+4)

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A.

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Mr. Doyle mowed 2\5ths of his lawn. His son mowed 1\3rd of it. Who mowed most of the lawn? How much of the lawn still needs to b
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Answer:

Step-by-step explanation:

Dad:  2/5

Son:  1/3

<u>Who mowed most of the lawn? </u> Dad, of course.  2/5 is larger than 1/3.  2/5 is 40% and 1/3 is 33.333%

<u>How much of the lawn still needs to be mowed?  </u>

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4/15 left to be mowed.

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Son will mow 1/3 of 4/15, so (1/3)*(4/15) = 4/45 left of the original yard

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