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3 years ago

If a =(1 2 3 4 5 then the number subsets a is

Mathematics

1 answer:

Romashka-Z-Leto [24]3 years ago

4 0

Answer:

Every choice doubles the number of subsets previously built, so the 4 subsets of {1,2} become 8 when we think of subsets of {1,2,3}. Then 16, and finally 32 subsets for {1,..5}.

Step-by-step explanation:

hopefully this helps!

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Does anyone know how to sovle this

Umnica [9.8K]

The 2 interior angles add to the exterior angle
26+13=x
39=x

x=39°

because

remember, all angles add to 180
26+13+BCA=180
39+BCA=180
minus 39 both sides
BCA=141
look, we want x

BC is a striaign line which is 180
BCA+x=180
141+x=180
minus 141 from both sides
x=39°

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3 years ago

An item has a listed price of $35. If the sales tax rate is 9%, how much is the sales tax (in dollars)?

olga_2 [115]

Answer:

$3.15

Step-by-step explanation:

tax is 9% or .09 of the cost

$35(.09) = $3.15

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3 years ago

What is the value of z , when c is 8 ?

Step2247 [10]

Answer:

547

Step-by-step explanation:

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3 years ago

Read 2 more answers

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bagirrra123 [75]

Answer:

7789 i think this is the answer

Step-by-step explanation:

6 0

3 years ago

13. Write

Bingel [31]

First off, we factor out the expression:

$\displaystyle \large{y = 2 {x}^{2} - 12x + 16} \\ \displaystyle \large{y = 2 ( {x}^{2} - 6x + 8) }$

In the bracket, separate 8 out of the expression.

$\displaystyle \large{y = 2[ ( {x}^{2} - 6x + 8)] }\\ \displaystyle \large{y = 2[ ( {x}^{2} - 6x) + 8]}$

In x^2-6x, find the third term that can make up or convert it to a perfect square form. The third term is 9 because:

$\displaystyle \large{ {(x - 3)}^{2} = {x}^{2} - 6x + 9}$

So we add +9 in x^2-6x.

$\displaystyle \large{y = 2[ ( {x}^{2} - 6x + 9) + 8]}$

Convert the expression in the small bracket to perfect square.

$\displaystyle \large{y = 2[ {(x - 3)}^{2} + 8]}$

Since we add +9 in the small bracket, we have to subtract 8 with 9 as well.

$\displaystyle \large{y = 2[ {(x - 3)}^{2} + 8 - 9]} \\ \displaystyle \large{y = 2[ {(x - 3)}^{2} - 1]}$

Then we distribute 2 in.

$\displaystyle \large{y = 2[ {(x - 3)}^{2} - 1]} \\$

$\displaystyle \large{y = 2[ {(x - 3)}^{2} - 1]} \\ \displaystyle \large{y = [2 \times {(x - 3)}^{2} ]+[ 2 \times ( - 1)] } \\ \displaystyle \large{y = 2 {(x - 3)}^{2} - 2 }$

Remember that negative multiply positive = negative.

Hence the vertex form is y = 2(x-3)^2-2 or first choice.

4 0

3 years ago

If a =(1 2 3 4 5 then the number subsets a is ​

If a =(1 2 3 4 5 then the number subsets a is