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3 years ago

I need help cand someone help me find this answer

Mathematics

1 answer:

MAXImum [283]3 years ago

3 0

Answer:

725.7 m²

Step-by-step explanation:

A=2πrh

r=16 1/2 ÷ 2 = 8 1/4

A= 2π(8.25)(14)=725.7

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What is the constant in this expression?: 42x - 15 y + 3 ?

dlinn [17]

Answer:

The constant in your equation is 3

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3 years ago

Lloyd's Cereal company packages cereal in 1 pound boxes (16 ounces). A sample of 16 boxes is selected at random from the product

gtnhenbr [62]

Answer:

The probability that the amount dispensed per box will have to be increased is 0.0062.

Step-by-step explanation:

Consider the provided information.

Sample of 16 boxes is selected at random.

If the mean for 1 hour is 1 pound and the standard deviation is 0.1

1 Pound = 16 ounces , then 0.1 Pound = 16/10 = 1.6 ounces

Thus: μ = 16 ounces and σ = 1.6 ounces.

Compute the test statistic $z=\frac{\bar x-\mu}{\frac{\sigma}{\sqrt{n}}}$

$z=\frac{15-16}{\frac{1.6}{\sqrt{16}}}$

$z=\frac{-1}{\frac{1.6}{4}}$

$z=\frac{-1}{0.4}$

$z=-2.5$

By using the table.

P value = P(Z<-250) = 0.0062

Thus, the probability that the amount dispensed per box will have to be increased is 0.0062.

7 0

3 years ago

Evaluate, please help

guapka [62]

(6^2/-4)+(6^2/-2)

(36/-4)+(36/-2)

-9+(-18)

= -27

8 0

4 years ago

Read 2 more answers

2x + y = 15 x + y = 10

Artyom0805 [142]

Answer:

2x+y=15x+y=10

Consider the first equation. Subtract 15x from both sides.

2x+y−15x=y

Combine 2x and −15x to get −13x.

−13x+y=y

Subtract y from both sides.

−13x+y−y=0

Combine y and −y to get 0.

−13x=0

Divide both sides by −13. Zero divided by any non-zero number gives zero.

x=0

Consider the second equation. Insert the known values of variables into the equation.

15×0+y=10

Multiply 15 and 0 to get 0.

0+y=10

Anything plus zero gives itself.

3 0

3 years ago

-8-575-78<br> How do I round my answer to the nearest ten thousandth

Goryan [66]

you can't

Or you can just say it is rounded to 0

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3 years ago

I need help cand someone help me find this answer ​

I need help cand someone help me find this answer