Answer:
-127
Step-by-step explanation:
Let the lengths of the sides of the rectangle be x and y. Then A(Area) = xy and 2(x+y)=300. You can use substitution to make one equation that gives A in terms of either x or y instead of both.
2(x+y) = 300
x+y = 150
y = 150-x
A=x(150-x) <--(substitution)
The resulting equation is a quadratic equation that is concave down, so it has an absolute maximum. The x value of this maximum is going to be halfway between the zeroes of the function. The zeroes of the function can be found by setting A equal to 0:
0=x(150-x)
x=0, 150
So halfway between the zeroes is 75. Plug this into the quadratic equation to find the maximum area.
A=75(150-75)
A=75*75
A=5625
So the maximum area that can be enclosed is 5625 square feet.
if u multiply a negative and a negative sign you will get a positive so the answer will be 276
Answer:
Option (3)
Step-by-step explanation:
Track is shaped as a rectangle with a semicircle on either side.
Therefore, length of the track = 2(Length of rectangle) + perimeter of a complete circle formed by joining the semicircles on each side.
= 2(96) + 2πr
= 
= 192 + 35π
= 192 + 109.9
= 301.9 m
Since, Jake plans to run four laps.
Therefore, distance covered by Jake = 4 × 301.9
= 1207.6 m
Option (3) will be the correct option.
It would be Adjacent/hypotenus which is 36/39 and when simplified the answer is 12/13
