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Nimfa-mama [501]
3 years ago
11

Figure ABCD is transformed to A′B′C′D′, as shown: A coordinate plane is shown. Figure ABCD has vertices A at 3 comma 1, B at 3 c

omma 4, C at 5 comma 5 and D at 5 comma 3. Figure A prime B prime C prime D prime has vertices A prime at negative 5 comma 1, B prime at negative 5 comma 4, C prime at negative 7 comma 5 and D prime at negative 7 comma 3. Which of the following sequences of transformations is used to obtain figure A′B′C′D′ from ABCD? (4 points) Reflection about the x-axis followed by a translation right by 2 units Reflection about the y-axis followed by a translation left by 2 units Counterclockwise rotation by 90 degrees about the origin followed by a translation right by 2 units Counterclockwise rotation by 90 degrees about the origin followed by a translation left by 2 units
Mathematics
1 answer:
Marta_Voda [28]3 years ago
7 0
4+4(7x5)= 7/6+58029+>667482+ªº993”QnQ no seeeeeeeeeeeeeeeeeeeeeeeeee
Eeeeeeeeeeeeeee mucho UwU
QwQ
Chauuuuu
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Needd helpp pleasee!!!!!
Morgarella [4.7K]

Number of game tokens is the label on x-axis.

<u>Step-by-step explanation</u>:

The equation is y = 0.5x + 3

Given,

  • Admission charge = $3
  • Cost of game token = $0.5 per game.

Total cost = admission charge + cost for number of game token

where,

  • y represents the total cost
  • x represents the number of game tokens.
7 0
3 years ago
How long does it take to double a $1,000 investment that pays 6.5% annual interest, compounded monthly?
ahrayia [7]
2p=p(1+0.065/12)^12t
2=(1+0.065/12)^12t
Solve for t
T= [log(2)/ log(1+0.065/12)] /12
T= 10.7 years or if you want to round it would be 11

Answer: 10.7 years or 11 years

Answer: You can use the compound interest formula: A=P(1+interest)^n

A=the new capital
P=the capital invested
n= the #of monthly


Hope this helps (:
3 0
3 years ago
Read 2 more answers
At 8:00 am, here's what we know about two airplanes: Airplane #1 has an elevation of 80870 ft and is decreasing at the rate of 4
wel

Let's begin by listing out the information given to us:

8 am

airplane #1: x = 80870 ft, v = -450 ft/ min

airplane #2: x = 5000 ft, v = 900ft/min

1.

We must note that the airplanes are moving at a constant speed. The equation for the airplanes is given by:

\begin{gathered} E=x_1+vt----1 \\ E=x_2+vt----2 \\ where\colon E=elevation,ft;x=InitialElevation,ft; \\ v=velocity,ft\text{/}min;t=time,min \\ x_1=80,870ft,v=-450ft\text{/}min \\ E=80870-450t----1 \\ x_2=5,000ft,v=900ft\text{/}min \\ E=5000+900t----2 \end{gathered}

2.

We equate equations 1 & 2 to get the time both airlanes will be at the same elevation. We have:

\begin{gathered} 5000+900t=80870-450t \\ \text{Add 450t to both sides, we have:} \\ 900t+450t+5000=80870-450t+450t \\ 1350t+5000=80870 \\ \text{Subtract 5000 from both sides, we have:} \\ 1350t+5000-5000=80870-5000 \\ 1350t=75870 \\ \text{Divide both sides by 1350, we have:} \\ \frac{1350t}{1350}=\frac{75870}{1350} \\ t=56.2min \\  \\ \text{After }56.2\text{ minutes, both airplanes will be at the same elevation} \end{gathered}

3.

The elevation at that time (when the elevations of the two airplanes are the same) is given by substituting the value of time into equations 1 & 2. We have:

\begin{gathered} E_1=80870-450t \\ E_1=80870-450(56.2) \\ E_1=80870-25290 \\ E_1=55580ft \\  \\ E_2=5000+900t \\ E_2=5000+900(56.2) \\ E_2=5000+50580 \\ E_2=55580ft \\  \\ \therefore E_1\equiv E_2=55580ft \end{gathered}

6 0
1 year ago
Find the angle sum of the irregular polygon using the formula S= 180(n-2).
lesya [120]

Answer:

  720°

Step-by-step explanation:

The "n" in the formula refers to the number of sides. The polygon shown has 6 sides, so the sum of interior angles is ...

  S = 180°(6 -2) = 720°

7 0
3 years ago
I will give BRAINLIEST!!! middle school math...
JulijaS [17]

Answer:

Solution given:

A(x,y))----reflection about x axis--->A'(x,-y)

P(2,1)---reflection about x axis----->Q(2,-1)

R(-6,-5)----reflection about x axis-->S(-6,5)

3 0
3 years ago
Read 2 more answers
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