Answer:
There are 420 windows.
Step-by-step explanation:
If the ground floor is part of the 20 =>
20.20=400
There are 400 windows.
If the ground floor is not part of the 20=>
20.20+20=420
There are 420 windows.
Answer:
x = 2y + 1 + (z/2)
Step-by-step explanation:
Just manipulate the equation to isolate x.
Answer:
the ratio is 10:12 and if you were to write it in a fraction you get 10/12 which can be simplified as 5/6
Answer:
the Europeans got the better deal from the Colombian Exchange
Step-by-step explanation:
In general, one would have to say that the Europeans got the better deal from the Columbian Exchange in that it facilitated the eventual establishment of colonies in the New World. That's not to say that it was all one-way traffic; however, the people of the New World undoubtedly benefitted in both the short and long-term by the introduction of crops and livestock. But such benefits proved to be more keenly felt by subsequent waves of European settlers than America's indigenous population.
After all, it wasn't much good for Native-Americans to have all these crops and all this livestock if, in due course, there'd be less land available for their use due to increased colonization. The indigenous peoples also suffered terribly from the introduction of diseases such as measles and smallpox, for which they had no natural immunity. It's difficult, then, to avoid the conclusion that the Europeans got the better deal from the Columbian Exchange (as it was probably intended that they should).
simply -
The Natives did benefit, but only for a short while, and the Europeans benefited the most
Kono Dio Da!!!
Answer:
Step-by-step explanation:
Let us denote probability of spoilage as follows
Transformer spoilage = P( T ) ; line spoilage P ( L )
Both P ( T ∩ L ) .
Given
P( T ) = .05
P ( L ) = .08
P ( T ∩ L ) = .03
a )
For independent events
P ( T ∩ L ) = P( T ) x P ( L )
But .03 ≠ .05 x .08
So they are not independent of each other .
b )
i )
Probability of line spoilage given that there is transformer spoilage
P L/ T ) = P ( T ∩ L ) / P( T )
= .03 / .05
= 3 / 5 .
ii )
Probability of transformer spoilage but not line spoilage.
P( T ) - P ( T ∩ L )
.05 - .03
= .02
iii )Probability of transformer spoilage given that there is no line spoilage
[ P( T ) - P ( T ∩ L ) ] / 1 - P ( L )
= .02 / 1 - .08
= .02 / .92
= 1 / 49.
i v )
Neither transformer spoilage nor there is no line spoilage
= 1 - P ( T ∪ L )
1 - [ P( T ) + P ( L ) - P ( T ∩ L ]
= 1 - ( .05 + .08 - .03 )
= 0 .9
