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Andrew [12]
3 years ago
10

#7: Five containers, each weighing the same amount, were placed on a 30-pound

Mathematics
1 answer:
Ede4ka [16]3 years ago
6 0

Answer:

Option (B)

Step-by-step explanation:

Let the weight of one container = x pounds

Therefore, weight of 5 containers = 5x pounds

Weight of the platform = 30 pounds

Total weight of the platform and containers = (5x + 30) pounds

If the maximum weight that can be lifted by the cable = 780 pounds

Inequality representing this situation will be,

(5x + 30) < 780

5x < 780 - 30

5x < 750

x < 150

Therefore, Option (B) is the answer.

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Add 7 to me. Then subtract 10. If you subtract 5 and then add 9, you get 14. What number am I?
Vesna [10]

Answer:

your answer is 13.

am I correct.

3 0
3 years ago
at 2 P.M the level of the water in the pool was 10 feet. At 6 P.M the level of water was 2 feet. Find the constant rate of chang
Anna35 [415]
Decreases by 2ft every hour

3 0
4 years ago
What is the length of the hypotenuse? 55 ft and 48 ft
34kurt

Answer:

\sqrt{55^2+ 48^2} = 73

Step-by-step explanation:

c=\sqrt{a^2 + b^2}

6 0
3 years ago
What are the x- and y-intercepts of the graph of 3x - 4y = 9?​
coldgirl [10]

Answer:

The X and Y intercepts and the Slope are called the line properties. We shall now graph the line -3x-4y-9 = 0 and calculate its properties. Graph of a Straight Line : Calculate the Y-Intercept : Notice that when x = 0 the value of y is 9/-4 so this line "cuts" the y axis at y=-2.25000. y-intercept = 9/-4 = -2.25000.

Step-by-step explanation:

Find the X and Y Intercepts 3x-4y=9. 3x − 4y = 9 3 x - 4 y = 9. Find the x-intercepts. Tap for more steps... To find the x-intercept (s), substitute in 0 0 for y y and solve for x x. 3 x − 4 ⋅ 0 = 9 3 x - 4 ⋅ 0 = 9. Solve the equation. Tap for more steps... Simplify 3 x − 4 ⋅ 0 3 x - 4 ⋅ 0.

6 0
3 years ago
The annual tuition at a specific college was $20,500 in 2000, and $45,4120
nika2105 [10]

Answer: the tuition in 2020 is $502300

Step-by-step explanation:

The annual tuition at a specific college was $20,500 in 2000, and $45,4120 in 2018. Let us assume that the rate of increase is linear. Therefore, the fees in increasing in an arithmetic progression.

The formula for determining the nth term of an arithmetic sequence is expressed as

Tn = a + (n - 1)d

Where

a represents the first term of the sequence.

d represents the common difference.

n represents the number of terms in the sequence.

From the information given,

a = $20500

The fee in 2018 is the 19th term of the sequence. Therefore,

T19 = $45,4120

n = 19

Therefore,

454120 = 20500 + (19 - 1) d

454120 - 20500 = 19d

18d = 433620

d = 24090

Therefore, an

equation that can be used to find the tuition y for x years after 2000 is

y = 20500 + 24090(x - 1)

Therefore, at 2020,

n = 21

y = 20500 + 24090(21 - 1)

y = 20500 + 481800

y = $502300

6 0
3 years ago
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