What is the area of this figure?<br><br> Enter your answer in the box.<br><br> mm²

Find the missing segment in the image below

Aleksandr-060686 [28]

Answer:

again it has a ratio

Step-by-step explanation:

follow this steps.

firstly look at the side and you got the ratio 24/16

secondly write 42/? and multiply by 24/16

the answer is ?*24=42*16 and divide it by 8 and write again ?*3=42*2 and finally the answer is ?=28

7 0

3 years ago

Read 2 more answers

You buy a pair of pants. The original cost of the pants is $30.00. The pants are on sale for 20% off.

AURORKA [14]

Answer:

i think it's $24

5 0

2 years ago

Student Council is selling candy grams. They are using the formula

Luden [163]

Answer:

Our equation is:

y = f(x) = 2.5*x

The domain is the set of the values of x.

The range is the set of the values of y.

They must sell between 55 and 60 candy grams to meet their goal.

If we assume these as restrictions for the domain, then the minimum value of x is 55, and the maximum value of x is 60.

Then the domain is:

D: 55 ≤ x ≤ 60.

Now that we know the domain, we can find the range.

As our equation is linear with a positive coefficient, the minimum in the range will coincide with the minimum in the domain, then we have:

y = 2.5*55 = 137.5

And the maximum will coincide with the maximum in the domain:

y = 2.5*60 = 150.

Then the range is:

y = 137.5 ≤ y ≤ 150

7 0

3 years ago

Consider quadrilateral BCEF inscribed in circle A. Diagonals EB and CF intersect at point D. Select all the statements that are

Elena L [17]

Answer:

$m\angle ECB+m\angle EFB=180$

$m\angle CDB\cong m\angle EDF$

$m\angle CDB+m\angle DCB+m\angle CBD=180 \degree$

Step-by-step explanation:

From the diagram, quadrilateral BCEF is a cyclic quadrilateral.

Opposite angles if a cyclic quadrilateral sum up to 180°

$m\angle ECB+m\angle EFB=180$

The diagonals intersect at D to form two pairs of vertical angles, and vertical angles are congruent.

$m\angle CDB\cong m\angle EDF$

Also sum of angles in triangle CBD is 180°.

$m\angle CDB+m\angle DCB+m\angle CBD=180 \degree$

6 0

2 years ago

Hector is flying a kite. He has let out 86 feet

Kaylis [27]

Answer:

Hector's kite is 61.84 feet from the ground.

Step-by-step explanation:

The angle of elevation of the kite is 42°15’30” when converted to decimals, it is $42.258333^{0}$ ≅ $42.26^{0}$

Let the height of the kite to the horizontal of angle of elevation be represented as x. Applying the trigonometric function to the sketch of Hector's kite,

Sin θ = $\frac{opposite}{hypotenus}$

Sin $42.26^{0}$ = $\frac{x}{86}$

⇒ x = 86 x Sin $42.26^{0}$

= 86 x 0.6725

= 57.835

x ≅ 57.84 feet

The height of Hector's kite from the ground = x + 4

= 57.84 + 4

= 61.84 feet

7 0

3 years ago

What is the area of this figure? Enter your answer in the box. mm²