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xxTIMURxx [149]
2 years ago
5

Symposium is part of a larger work referred to as Plato's Dialogues. Wishart and Leach† found that about 21.4% of five-syllable

sequences in Symposium are of the type in which four are short and one is long. Suppose an antiquities store in Athens has a very old manuscript that the owner claims is part of Plato's Dialogues. A random sample of 498 five-syllable sequences from this manuscript showed that 129 were of the type four short and one long. Do the data indicate that the population proportion of this type of five-syllable sequence is higher than that found in Plato's Symposium? Use ???? = 0.01.
Mathematics
1 answer:
notsponge [240]2 years ago
7 0

Complete Question

ymposium is part of a larger work referred to as Plato's Dialogues. Wishart and Leach† found that about 21.4% of five-syllable sequences in Symposium are of the type in which four are short and one is long. Suppose an antiquities store in Athens has a very old manuscript that the owner claims is part of Plato's Dialogues. A random sample of 498 five-syllable sequences from this manuscript showed that 129 were of the type four short and one long. Do the data indicate that the population proportion of this type of five-syllable sequence is higher than that found in Plato's Symposium? Use = 0.01.  

a. What is the value of the sample test statistic? (Round your answer to two decimal places.)  

b. Find the P-value of the test statistic. (Round your answer to four decimal places.)

Answer:

a) Z=2.45

b) P Value=0.0073

Step-by-step explanation:

From the question we are told that:

Probability of Wishart and Leach P=21.4=>0.214

Population Size N=498

Sample size n=12

Therefore

P'=\frac{129}{498}

P'=0.2590

Generally the Null and Alternative Hypothesis is mathematically given by

H_0:P=0.214

H_a:=P>0.214

Test Statistics

Z=\frac{P'-P}{\sqrt{\frac{P(1-P)}{n}}}

Z=\frac{0.2590-0.214}{\sqrt{\frac{0.214(1-0.214)}{498}}}

Z=2.45

Therefore P Value is given as

P Value =P(Z\geq 2.45)

P Value =1-P(Z\leq 2.45)

P Value =1-0.99268525

P Value=0.0073

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A toy car costing $50 is reduced by 10% in the sale. how much money is it reduced by?
atroni [7]

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$5

Step-by-step explanation:

10% = 10/100 = 1/10.

1/10 of 50 = 5

5 0
3 years ago
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Ariana bought 5 dozen pears at $36 per dozen . She discovered that 7 were rotten and she sold the rest at $4.50 each . Calculate
GrogVix [38]

Step-by-step explanation:

1 dozen = 12 pears

12 pears = $36

1 pear = 36/12 = $3

Total Cost of Pears = No. of pears x price of 1 pear

= (5x12) x 3

= 60 x 3

= $180

Sale of Pears = Price per pear x (Total Pears bought - Rotten Pears)

= $4.50 x (5x12-7)

= $4.50 x 53

= $238.50

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= $238.50 - $180

= $58.50

Ariana made a profit of $58.50.

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25-3x-2-4x+5 has how many coefficients and how many expressions
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3 0
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Question 9 of 10
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Answer:

D

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7 0
2 years ago
Item 10 Find the amount of time. I=$450, P=$2400, r=7.5%
Alex787 [66]
The answer is:  "2.5 years" . 
___________________________________________________
  Note:   I = P * r * t  ;    { " Interest = Principal * rate * time "} ; 

          →     Solve for "t" {"time", in years} ;  

Divide each side of the equation by "{P * r}"  ;  
   to isolate "t" on one side of the equation ;

→  I / (P * r)  = {P * r * t) / (P * r} ; 

to get:  " I / (P * r) = t " ;  

  ↔  t = I / (P * r) ; 

Given:  I = $450 ;  
  
            <span>P = $2400 ; 

            r = 7.5% = 7.5/100 = 0.075 ; 

Plug in these values into the formula to solve for the time, "t" :

        </span>→  t  =  I  /  (P  *  r )   ;  

                 =  $450  /   (<span>$2400 * 0.075) ;

                 =  </span>$450  /   ($2400 * 0.075) ;

                 =  $450 / $180 ; 

                 =  $45 / $18 ; 

                 =  ($45 ÷ 9) / ($18 ÷ 9) 

                 =  $5 / $2 ; 

                 =  2.5  ; 

        →  t  =  2.5 years.
_______________________________________________________
The answer is:  "2.5 years" . 
_______________________________________________________
7 0
3 years ago
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