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sergejj [24]
2 years ago
11

Amanda wants to attend Baylor University for her 4-year college. She is a National Merit Scholar and scores a 1500 on her SATs.

This qualifies her for a yearly scholarship of $44,194. How much additional money does she need to have to attend Baylor for 4 years?
Mathematics
1 answer:
EleoNora [17]2 years ago
5 0

Answer:

$58,544

Step-by-step explanation:

Given that Baylor charges tuition fees at $41,194, Room at $13038 and Required fees at $4598 p.a. We also know that the scholarship pays $44194 p.a.

#The additional money for the four years is the total  minus the scholarship  multiplied by 4 yrs:

C_{p.a}=Tution+Room+Required\\\\=41194+13038+4598\\\\=58830\\\\Scholarship=44194\\\\\bigtriangleup p.a=58830-44194\\\\=14636

The additional cost to attend the college for the next four years is:

\bigtriangleup p.a=14636\\\\\sum{\bigtriangleup p.a _i}=4\times 14636\\\\=58544

Hence, Amanda needs an additional $58,544 to attend Baylor for the 4 years.

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Factor the expression. 9b2 – 25
rewona [7]

Answer: (3b + 5)(3b - 5)

Because both terms, 9b² and 25, are perfect squares, you can factor by taking the square roots of both terms.

The square root of 9b² is 3b (3b × 3b = 9b²).

The square root of 25 is 5 (5 × 5 = 25).

9b² - 25 has a negative, so the factored expression would be

(3b + 5)(3b - 5). The signs (+ and -) alternate in this case because the  expression, 9b² - 25, has no middle term.

You can check your work by using FOIL. See the attachment below.

F irst

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5 0
2 years ago
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Elan Coil [88]

Answer:

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Step-by-step explanation:

count two up, and 5 to the right

8 0
3 years ago
How many ways can six of the letters of the word ALGORITHM be selected 8. How many ways can the letters of the word ALGORITHM be
SCORPION-xisa [38]
<h2>Answer with explanation:</h2>

The number of letters in word "ALGORITHM" = 9

The number of combinations to select r things from n things is given by :-

C(n,r)=\dfrac{n!}{r!(n-r)!}

Now, the number of combinations to select 6 letters from 9 letters will be :-

C(9,8)=\dfrac{9!}{6!(9-6)!}=\dfrac{9\times8\times7\times6!}{6!\times3!}=84

Thus , the number of ways can six of the letters of the word ALGORITHM=84

The number of ways to arrange n things in a row :n!

So, the number of ways can the letters of the word ALGORITHM be arranged in a be seated together in the row :-

9!=362880

If GOR comes together, then we consider it as one letter,  then the total number of letters will be = 1+6=7

Number of ways to arrange 9 letters if "GOR" comes together :-

7!=5040

Thus, the number of ways to arrange 9 letters if "GOR" comes together=5040

3 0
3 years ago
The profits of mr cash’s company is represented by the equation p(t)=-3t^2+18t-4, where p(t) is the amount of profit in hundreds
eduard
We have that

<span>p(t)=-3t^2+18t-4

using a graphing tool, we can see the maximum of the graph
(see the attached figure)

A) </span><span>In what year of operation does Mr. Cash’s business show maximum profit?

</span>Mr. Cash’s business show maximum profit at year 3 (maximum in the parabole)

<span>B) What is the maximum profit? 

23 (hundred of thousand of dollars) = 2.300.000 dollars

</span>c) What time will it be two late?
 
(This is the time when the graph crosses zero and the profits turn into losses )

5.77 years, or an estimate of about  69 months.

4 0
3 years ago
What value of c makes x2 − 24x + c a perfect square trinomial?<br><br> −144<br> −48<br> 48<br> 144
NARA [144]
I believe that the answer is 144 

8 0
3 years ago
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