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Leno4ka [110]
3 years ago
13

Timothy was given three and four sixths bags of marbles and lost two and one fourth bags at the beach. How many bags of marbles

does Timothy have left?
six and four twenty fourths bags of marbles
five and ten twenty fourths bags of marbles
one and four twenty fourths bags of marbles
one and ten twenty fourths bags of marbles
Mathematics
2 answers:
charle [14.2K]3 years ago
6 0
The right answer is 1 5/12 = 1 10/24 ! U just divide 10 and 24 by two <33
mamaluj [8]3 years ago
4 0

Answer: 1 and 5/12

Step-by-step explanation: A little sloppy but you needed to find the common denominator and then you would multiply them if you need a more detailed answer I can come again

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Hello please help thanks
daser333 [38]

Answer:

1 and 2 SORRY IF I AM WRONG

8 0
3 years ago
There is a bag with only red marbles and blue marbles. The probability of randomly choosing a red marble is 2 9 . There are 63 m
Tatiana [17]

The main idea is the number of marbles and the denominator of the probability. All you have to do is multiply the fraction by a fraction which is equal to 1 which makes the denominator equal to 63. We know 63 is a multiple of 9. 9 goes 7 times in 63 so we multiple the fraction \frac{2}{9} with \frac{7}{7} which gives, \frac{2 * 7}{9 * 7} which when evaluated gives \frac{14}{63} and the numerator is the number of red marbles in the bag. So there are 14 red marbles in the bag :D

7 0
3 years ago
Solve the following quadratic equation using the quadratic formula.
sdas [7]
ax^2+bx+c=0\\\\\Delta=b^2-4ac\\\\x_1=\dfrac{-b-\sqrt\Delta}{2a};\ x_2=\dfrac{-b+\sqrt\Delta}{2a}

<span>5x^2-8x+5=0\to a=5;\ b=-8;\ c=5\\\\\Delta=(-8)^2-4\cdot5\cdot5=64-100=-36\\\\\sqrt\Delta=\sqrt{-36}=6i

x_1=\dfrac{-(-8)-6i}{2\cdot5}=\dfrac{8-6i}{10}=\dfrac{4-3i}{5}\\\\x_2=\dfrac{-(-8)+6i}{2\cdot5}=\dfrac{8+6i}{10}=\dfrac{4+3i}{5}
</span>
6 0
3 years ago
Read 2 more answers
What is 5 8/12 in simplest form?
bekas [8.4K]
5 8/12 in the simplest form is 17/3
8 0
3 years ago
Read 2 more answers
What is the input-output table for the function f(x) = 3x^2-x+4
mojhsa [17]

Answer:

Step-by-step explanation:

The input-output table can be made by putting value of x and finding the value of f(x)

f(x) = 3x^2-x+4

f(0) = 3(0)^2-0+4 = 0-0+4 = 4

f(1) = 3(1)^2-1+4 = 3-1+4 = 2+4 =6

f(2) = 3(2)^2-2+4 = 3(4)-2+4 = 12-2+4 = 10+4 = 14

f(3) = 3(3)^2-3+4 = 3(9)-3+4 = 27-3+4 = 24+4 = 28

So put value of x and find f(x) and fill the input-output table.

x  f(x)

0   4

1    6

2   14

3    28

3 0
3 years ago
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