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Yuri [45]
3 years ago
10

Hellppo due June 30th

Mathematics
2 answers:
Leya [2.2K]3 years ago
4 0
Basically find the area of the bigger and smaller circle

a = pi * r^2

a = 3.14 * 7^2
a = 3.14 * 49
a = 153.86

a = 3.14 * 11^2
a = 3.14 * 121
a = 379.94

subtract the smaller area from the larger area:

379.94 - 153.86 = 226.08 sq cm
Ivan3 years ago
3 0

Answer:

Step-by-step explanation:

Non-shaded region area:

A= 3.14 x 7^2=153.86 cm²

The whole circle area:

A=3.14 x 11^2= 379.94 cm²

Area for ONLY the shaded region:

A= 379.94 - 153.86= 226.08 cm²

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Express the angle in radian measure.<br> -135°
ololo11 [35]
-3/4 pi

Do the equation -135/180 = 180/pi and simplify
5 0
3 years ago
Read 2 more answers
Find the components of the vertical force Bold Upper Fequalsleft angle 0 comma negative 8 right anglein the directions parallel
nydimaria [60]

Answer with Step-by-step explanation:

We are given that

F=<0,-8>=0i-8j=-8j

\theta=\frac{\pi}{3}

The component of force is divided into two direction

1.Along the plane

2.Perpendicular to the plane

1.The vector parallel to the plane will be=r=cos\frac{\pi}{3}i-sin\frac{\pi}{3}j=\frac{1}{2}i-\frac{\sqrt 3}{2}j

By using cos\frac{\pi}{3}=\frac{1}{2},sin\frac{\pi}{3}=\frac{\sqrt 3}{2}

Force along the plane will be=\mid F_x\mid=F\cdot r

Force along the plane will be =\mid F_x\mid=F\cdot (\frac{1}{2}i-\frac{\sqrt 3}{2}j)=-8j\cdot(\frac{1}{2}i-\frac{\sqrt 3}{2}j)=8\times \frac{\sqrt 3}{2}=4\sqrt 3N

By using i\cdot i=j\cdoty j=k\cdot k=1,i\cdot j=j\cdot k=k\cdot i=j\cdot i=k\cdot j=i\cdot k=0

Therefore, force along the plane=\mid F_x\mid(\frac{1}{2}i-\frac{\sqrt 3}{2}j)=4\sqrt 3(\frac{1}{2}i-\frac{\sqrt 3}{2}j)

2.The vector perpendicular to the plane=r=-sin\frac{\pi}{3}-cos\frac{\pi}{3}=-\frac{\sqrt 3}{2}i-\frac{1}{2}j

The force perpendicular to the plane=\mid F_y\mid=F\cdot r=-8j(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)

The force perpendicular to the plane=4N

Therefore, F_y=4(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)

Sum of two component of force=F_x+F_y=4\sqrt 3(\frac{1}{2}i-\frac{\sqrt 3}{2}j)+4(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)

Sum of two component of force=2\sqrt 3i-6j-2\sqrt3 i-2j=-8j

Hence,sum of two component of forces=Total force.

6 0
3 years ago
Help!!!!!!!!!!!!!!!!Will mark BRAINLIEST​
Pani-rosa [81]

Answer:

Step-by-step explanation:

1. true

2. true

3. false ( pie chart )

4. true

5. false ( y axis )

6. true

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Hope this helps

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6 0
4 years ago
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The answer would be the third choice

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