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Sergio039 [100]
3 years ago
5

Which expressions are polynomials? Select each correct answer. 30y^2 30y^2+x 30y2x 30y2+x12

Mathematics
1 answer:
gregori [183]3 years ago
6 0

To know which of the following expressions are polynomials, let us look at the definition of a polynomial:

Polynomial is derived from poly- (which means "many") and -nomial (meaning "term"), so it says "many terms".

For an instance: 2x^2y+2y^2 is a polynomial, but 4xy^2 is not a polynomial because it contains single term only.

We must keep in mind that in polynomial it can have variables, constants, and exponents but it can never have division by a variable.

Now lets, look at the

30y^2 since it has got one term it can not be a polynomial.

30y^2+x: it has got <em>more than one term</em> therefore, <em>it is a polynomial. </em>

30y^2x: again it has got just one term so it is not a polynomial.

30y^2+x^{12}: Since it has got <em>more than one term</em>, so again<em> it is a polynomial. </em>

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A certain virus is dying off at a rate of 18% per hour. Initially there were
djyliett [7]

Answer:

3 strain would still alive after 48 hours

Step-by-step explanation:

Initial population of virus = 40000 grams

A certain virus is dying off at a rate of 18% per hour.

We are supposed to find  how much of the  strain would still be alive after 48 hours

Formula : N(t)=N_0(1-r)^t

N_0=Initial population

N(t)= Population after t hours

r = rate of decrease = 18% = 0.18

t = time = 48 hours

So,the  strain would still be alive after 48 hours=40000(1-0.18)^{48}=2.91 \sim 3

Hence 3 strain would still alive after 48 hours

3 0
3 years ago
The Venn diagram shows the results of two events resulting from rolling a number cube.
tankabanditka [31]

Answer:

P(A|B)=\frac{2}{3}

P(A)*P(B)=\frac{1}{3}

P(A) =\frac{2}{3}

P(B) =\frac{1}{2}.

Step-by-step explanation:

We use the Venn diagram to calculate the desired probabilities.

Note that there are 6 possible results in the sample space

S = {1, 2, 3, 4, 5, 6}

Then note that in the region representing the intercept of A and B there are two possible values.

So

P (A\ and\ B) = \frac{2}{6} = \frac{1}{3}

In the region that represents event A there are 4 possible outcomes {4, 5, 1, 2}

So

P(A) = \frac{4}{6} = \frac{2}{3}

In the region that represents event B there are 3 possible outcomes {1, 2, 6}

So

P(B) = \frac{3}{6} = \frac{1}{2}.

Now

P(A | B)=\frac{P(A \ and\ B)}{P(B)}\\\\P(A | B)=\frac{\frac{1}{3}}{\frac{1}{2}}\\\\P(A|B)=\frac{2}{3}

P(A)*P(B)=\frac{2}{3}*\frac{1}{2}=\frac{1}{3}

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4 years ago
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Cloud [144]

Answer:

28

Step-by-step explanation:

Total amount of money she has=$40

Spends=12

40-12=28

She has $28 dollars left to spend on her binders.

3 0
3 years ago
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Answer:

4:3 or 1:0

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4 0
3 years ago
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there is an error because -9 x 1 = -9 not -1. But I would assume that you multiply -9×-1 and then -9×-2 ect.

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