Please help 2. Name the polar coordinates of the point graphed below.

Answer all the four q

Alik [6]

Answer:

MATHMATICS - MTHMTCS

SEPTEMBER - SPTMBR

ANCILLARY - NCLLR

PTERODACTYL-PTRDCTL

Hopefully this helps <3

4 0

3 years ago

A class has six boys and 15 girls what is the ratio of boys to girls

leva [86]

# of boys : # of girls
This can be written as
6:15
6 to 15, or
6/15

6 0

3 years ago

The following data summarizes results from 889 pedestrian deaths that were caused by accidents. If one of the pedestrian deaths

pickupchik [31]

Answer:

$P(A or B) = 0.291 +0.159 -0.0562=0.3938$

Step-by-step explanation:

Previous concepts

The total probability rule is "used to find the probability of an event, A, when you don’t know enough about A’s probabilities to calculate it directly. Instead, you take a related event, B, and use that to calculate the probability for A".

Solution to the problem

The data given:

Pedestrian

Intoxicated Not intoxicated Total

Intoxicated 50 91 141

Not intoxicated 209 539 748

Total 259 630 889

The rows on this case are associated to the tyep of Driver.

Let's define the following events:

A =Pedestrian was intoxicated

B= Driver was intoxicated

And we can find the probabilities for the events A and B like this with the info given:

$P(A) = \frac{50+209}{889}=0.291$

$P(B) = \frac{50+91}{889}=0.159$

We can find also the probaility that pedestrian was intoxicated AND driver was intoxicated, like this:

$P(A and B) = \frac{50}{889}=0.0562$

Because the intersection for the events A and B is 50 and the grand total is 889.

Now we can use the total rule of probability given by this:

$P(A or B) = P(A) +P(B) -P(A and B)$

And since w ehave everything to replace we got:

$P(A or B) = 0.291 +0.159 -0.0562=0.3938$

7 0

3 years ago

Line t has an equation of y=10x-8. Line u is perpendicular to line t and passes through (-10,-6). What is the equation of line u

Pachacha [2.7K]

Answer: y= $-\frac{1}{10} x-7$

Step-by-step explanation: The slope of a perpendicular line is always negative and the reciprocal (opposite fraction) of the regular slope so the slope would be $-\frac{1}{10}$ . If the line passes through (-10,-6) then the y intercept would be (0,-7) because every time x goes 10 right y goes down 1 because of the slope.

4 0

1 year ago

At one point the average price of regular unleaded gasoline was $3.41 per gallon. Assume that the standard deviation price per

Aleonysh [2.5K]

Answer:

a) $1-\frac{1}{k^2} =1- \frac{1}{2^2}= 1-0.25 = 0.75$

So we expected about 75% within two deviations from the mean

b) $1-\frac{1}{k^2} =1- \frac{1}{1.5^2}= 1-0.4444 = 0.556$

So we expected about 55.6% within 1.5 deviations from the mean

And the limits are:

$Lower = 3.41 -1.5*0.09 = 3.275$

$Upper = 3.41 +1.5*0.09 = 3.545$

c) We can calculate how many deviations we are within the mean with the limits with this formula:

$z =\frac{x-\mu}{\sigma}$

And using the lower limit we got:

$z = \frac{3.05-3.41}{0.09}=-4$

And with the upper limit we got:

$z = \frac{3.77-3.41}{0.09}=4$

So then the value of k =4 and the percentage is given by:

$1-\frac{1}{k^2} =1- \frac{1}{4^2}= 1-0.0625 = 0.9375$

Step-by-step explanation:

Previous concepts and Data given

$\mu =3.41$ reprsent the population mean

$\sigma=0.09$ represent the population standard deviation

The Chebyshev's Theorem states that for any dataset

• We have at least 75% of all the data within two deviations from the mean.

• We have at least 88.9% of all the data within three deviations from the mean.

• We have at least 93.8% of all the data within four deviations from the mean.

Or in general words "For any set of data (either population or sample) and for any constant k greater than 1, the proportion of the data that must lie within k standard deviations on either side of the mean is at least: $1-\frac{1}{k^2}$

Part a

For this case we can find the percentage required replaincg k =2 and we got:

$1-\frac{1}{k^2} =1- \frac{1}{2^2}= 1-0.25 = 0.75$

So we expected about 75% within two deviations from the mean

Part b

For this case we can find the percentage required replaincg k =2 and we got:

$1-\frac{1}{k^2} =1- \frac{1}{1.5^2}= 1-0.4444 = 0.556$

So we expected about 55.6% within 1.5 deviations from the mean

And the limits are:

$Lower = 3.41 -1.5*0.09 = 3.275$

$Upper = 3.41 +1.5*0.09 = 3.545$

Part c

We can calculate how many deviations we are within the mean with the limits with this formula:

$z =\frac{x-\mu}{\sigma}$

And using the lower limit we got:

$z = \frac{3.05-3.41}{0.09}=-4$

And with the upper limit we got:

$z = \frac{3.77-3.41}{0.09}=4$

So then the value of k =4 and the percentage is given by:

$1-\frac{1}{k^2} =1- \frac{1}{4^2}= 1-0.0625 = 0.9375$

3 0

3 years ago