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GuDViN [60]
3 years ago
13

Rearrange the following equation to solve for x. y=1/2x+10

Mathematics
1 answer:
maxonik [38]3 years ago
6 0
In order to solve this we must first,


Subtract both sides of the equation by 10,
y-10=1/2x

Now we have to multiply both sides by 2 so that only x is left.

2y-20=x


Therefore, x=2y-20
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-0.333333333 into a fraction
sweet [91]

Answer:

-1/3

Step-by-step explanation:

1/3 is 0.33333... and then you just put a negative sign in front of it.

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Solve the radical equation. m - 3 = √ 19 - 3m. Which is an extraneous solution to the radical equation?
Sphinxa [80]
The answer is m=5 and m=-2. There is no extraneous solution for this equation.

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3 years ago
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How large in square meters is the land area of australia (2941526 mi 2)?
cluponka [151]
2941526 mi^2
 The first thing you should know to solve this problem is the following conversion:
 1mi = 1609.34m
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 Answer: 
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8 0
3 years ago
The endpoints of are A(2, 3) and B(8, 1). The perpendicular bisector of is , and point C lies on . The length of is units. The c
Blababa [14]

Answer:

The Coordinates of Point C are C(5,2)

The slope of CD is 3  

The possible coordinates of point D(a,b) are (6, 5) and (4, -1)  

Step-by-step explanation:

According to the Question,

  • Given, The end points of AB are A(2,3) and B(8,1). The perpendicular Bisector of AB is CD, and point C lies on AB. The length of the CD is √10 units.

Now, Let The Coordinates of Point C are C( x , y ) .  

  • Thus, C( x , y ) = ((8 +2) / 2 , ( 1 + 3 )/ 2 ) ⇒ (10/2 , 4/2) ⇒ (5 , 2)

The Coordinates of Point C are C( x , y ) ⇒C(5, 2).  

And, The slope of AB = (1 - 3)/(8 - 2) ⇒ -2/6 ⇔ -1/3 .

  •       Thus, The slope of CD is  -1/(The slope of AB) =  -1/(-1/3) ⇔  3.

Let the coordinate of D be (a, b) then

⇒ √{ (b - 2)² +(a - 5)² } = √10

 on squaring both sides we get,

 ⇒ a² - 10a + 25 + b² - 4b + 4 = 10

 ⇒ a² + b² - 10a - 4b = - 19 ⇔⇔ (Equation 1)  

We Know, the slope of CD = 3

⇒Thus,  (b - 2)/(a - 5) = 3

⇒ b - 2 = 3a - 15

⇒ b = 3a - 13 ⇔⇔ (Equation 2)

Putting value of Equation 2 into Equation 1, We get

⇒a² + (3a - 13)² - 10a - 4(3a - 13) = - 19

⇒a² + 9a² - 78a + 169 - 10a - 12a + 52 = - 19

⇒10a² - 100a + 240 = 0

⇒a² - 10a + 24 = 0

⇒(a - 4)(a - 6) = 0

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Now,  

When a = 4 , b = 3(4) - 13 ⇒ 12 - 13 ⇒ b = -1

When a = 6, b = 3(6) - 13 ⇒ 18 - 13 ⇒ b = 5

Therefore, the possible coordinates of point D(a,b) are (6, 5) and (4, -1).

5 0
2 years ago
How to solve 10m-2/5=9 3/5
konstantin123 [22]
10m-2/5=9 and 3/5
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50m=50 ( i added 2 to both sides)

m=1 ( i divided by 50 to both sides to find m)

4 0
3 years ago
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