Answer:
Eastward distance of airplane = 903 miles
Northward distance of airplane = 1198 miles
Step-by-step explanation:
Consider the sketch attached below.
Let the Eastward distance be represented by x
let the Northward distance be represerted by y
The distance traveled = speed of plane x time
= 600 x 2.5 = 1500 miles
from basic trigonometry of a right angled triangle we have that




∴ Northward distance = 1198 miles
Eastward distance =903 miles
For (5, -2): -2 - 4(5) = -2 - 20 = -22 ≤ -5 [false]
For (-2, 1): 1 - 4(-2) = 1 + 8 = 9 ≥ -5 [true]
For (-4, 2): 2 - 4(-4) = 2 + 16 = 18 ≥ -5 [true]
For (1, -1): -1 - 4(1) = -1 - 4 = -5 ≥ -5 [true]
For (4, 0): 0 - 4(4) = 0 - 16 = -16 ≤ -5 [false]
Therefore, options B, C, and D satisfy the inequality.
Answer: 26 and 2
Step-by-step explanation: because it makes sense
The first quartile would be drawn at <span>3</span><span>, and the median would be drawn at 4.
So your answer is 3 and 4</span>