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3 years ago

Todd plans to swim 900 yards in a pool. So far Todd has swam 720 yards. What percentage of the total has Todd completed?

2 answers:

7 0

Ok, so the answer is 80%. How I got this, I did the cross-product method. On one side, I did x/100, and the other, I did 720/900. And I multiplied 720 by 100, and got 72,000. And I also did 900 Times x, and got 900x. So, the new equation is 72000 = 900x. I divided 72000 by 900, and got 80, which is the percentage. (Picture of Cross-Product Method)

ella [17]3 years ago

5 0

Answer:im pretty sure its 64.8

Step-by-step explanation:

You might be interested in

What number divided by -7 is equal to -15

steposvetlana [31]

Answer:

$x = -105$

Step-by-step explanation:

What number divided by -7 is equal to -15

∨ ∨ ∨ ∨ ∨

x ÷ -7 = -15

Multiply -7 to both sides:

$\frac{x}{-7}=15$

$x = -105$

3 0

2 years ago

7n2 + 5 = 453 Solve the quadratic function

Reptile [31]

7n^2 + 5 = 453

Subtract 5 from both sides:

7n^2 = 448

Divide both sides by 7:

N^2 = 64

Take the square root of both sides:

N = 8

8 0

3 years ago

Read 2 more answers

What is the quotient of 21.06 and 9

bekas [8.4K]

Answer:

21.06÷9 = 2 and 36 left over

Step-by-step explanation:

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3 years ago

For a giveaway, a local radio station is putting together goodie bags. The bags include tickets and posters. Each bag will recei

Doss [256]

36 goodie bags can be created in total because there are only 36 posters.

4 0

3 years ago

Read 2 more answers

A spacecraft is traveling with a velocity of v0x = 5320 m/s along the +x direction. Two engines are turned on for a time of 739

OlgaM077 [116]

Answer:

The velocities after 739 s of firing of each engine would be 6642.81 m/s in the x direction and 5306.02 in the y direction

Step-by-step explanation:

For a constant acceleration: $v_{f}=v_{0}+at$ , where $v_{f}$ is the final velocity in a direction after the acceleration is applied, $v_{0}$ is the initial velocity in that direction before the acceleration is applied, a is the acceleration applied in such direction, and t is the amount of time during where that acceleration was applied.
Then for the x direction it is known that the initial velocity is $v_{0x} =$ 5320 m/s, the acceleration (the applied by the engine) in x direction is $a_{x}$ 1.79 m/s2 and, the time during the acceleration was applied (the time during the engines were fired) of the is 739 s. Then: $v_{fx}=v_{0x}+a_{x}t=5320\frac{m}{s} +1.79\frac{m}{s^{2} }*739s=6642.81\frac{m}{s}$
In the same fashion, for the y direction, the initial velocity is $v_{0y} =$ 0 m/s, the acceleration in y direction is $a_{y}$ 7.18 m/s2, and the time is the same that in the x direction, 739 s, then for the final velocity in the y direction: $v_{fy}=v_{0y}+a_{y}t=0\frac{m}{s} +7.18\frac{m}{s^{2} }*739s=5306.02\frac{m}{s}$

8 0

3 years ago