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meriva
3 years ago
8

Todd plans to swim 900 yards in a pool. So far Todd has swam 720 yards. What percentage of the total has Todd completed?

Mathematics
2 answers:
lbvjy [14]3 years ago
7 0

Ok, so the answer is 80%. How I got this, I did the cross-product method. On one side, I did x/100, and the other, I did 720/900. And I multiplied 720 by 100, and got 72,000. And I also did 900 Times x, and got 900x. So, the new equation is 72000 = 900x. I divided 72000 by 900, and got 80, which is the percentage. (Picture of Cross-Product Method)

ella [17]3 years ago
5 0

Answer:im pretty sure its 64.8

Step-by-step explanation:

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Urgent!
Dovator [93]

Answer:

A. 1/3

Step-by-step explanation:

6/18 = 0.3333333333333333333

so in fraction it is 1/3

5 0
3 years ago
Read 2 more answers
Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10
zvonat [6]

The approximate difference in the ages of the two cars, which  depreciate to 60% of their respective original values, is 1.7 years.

<h3>What is depreciation?</h3>

Depreciation is to decrease in the value of a product in a period of time. This can be given as,

FV=P\left(1-\dfrac{r}{100}\right)^n

Here, (<em>P</em>) is the price of the product, (<em>r</em>) is the rate of annual depreciation and (<em>n</em>) is the number of years.

Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10%.

Suppose the original price of the first car is x dollars. Thus, the depreciation price of the car is 0.6x. Let the number of year is n_1. Thus, by the above formula for the first car,

0.6x=x\left(1-\dfrac{10}{100}\right)^{n_1}\\0.6=(1-0.1)^{n_1}\\0.6=(0.9)^{n_1}

Take log both the sides as,

\log 0.6=\log (0.9)^{n_1}\\\log 0.6={n_1}\log (0.9)\\n_1=\dfrac{\log 0.6}{\log 0.9}\\n_1\approx4.85

Now, the second car depreciates at an annual rate of 15%. Suppose the original price of the second car is y dollars.

Thus, the depreciation price of the car is 0.6y. Let the number of year is n_2. Thus, by the above formula for the second car,

0.6y=y\left(1-\dfrac{15}{100}\right)^{n_2}\\0.6=(1-0.15)^{n_2}\\0.6=(0.85)^{n_2}

Take log both the sides as,

\log 0.6=\log (0.85)^{n_2}\\\log 0.6={n_2}\log (0.85)\\n_2=\dfrac{\log 0.6}{\log 0.85}\\n_2\approx3.14

The difference in the ages of the two cars is,

d=4.85-3.14\\d=1.71\rm years

Thus, the approximate difference in the ages of the two cars, which  depreciate to 60% of their respective original values, is 1.7 years.

Learn more about the depreciation here;

brainly.com/question/25297296

4 0
2 years ago
Please help i will give you brainlest
Ugo [173]

Answer:

8 the answer is 8 if u need help just tell me cuz i just did this quiz and i got a 90 and i dont think urs is diffrent then mine

Step-by-step explanation:

8 0
3 years ago
Which set of three numbers could be the side lengths of a triangle?
Tresset [83]

Answer:

<h2>А. 3, 5, 7</h2><h2 />

Step-by-step explanation:

Because

7 - 3 = 4

7 + 3 = 10

then

7 - 3 < 5 < 7 + 3

the 3 other cases don’t fit with this rule.

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3 years ago
Is this problem convergent or divergent?
Svetllana [295]

Answer:

Its divergent

Step-by-step explanation:

<em><u>HOPE</u></em><em><u> </u></em><em><u>YOU</u></em><em><u> </u></em><em><u>LIKED</u></em><em><u> </u></em><em><u>IT</u></em>

6 0
2 years ago
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