Answer:
inside
√((5-(-5))^2+((-24)-(-8))^2)=√(10^2+16^2)=√356<25
<h3>The lateral area for the pyramid with the equilateral base is 144 square units</h3>
<em><u>Solution:</u></em>
The given pyramid has 3 lateral triangular side
The figure is attached below
Base of triangle = 12 unit
<em><u>Find the perpendicular</u></em>
By Pythagoras theorem

Therefore,

<em><u>Find the lateral surface area of 1 triangle</u></em>


<em><u>Thus, lateral surface area of 3 triangle is:</u></em>
3 x 48 = 144
Thus lateral area for the pyramid with the equilateral base is 144 square units
Answer:
x = 0.781 , y = -1.219
and
x = -1.281 , y = -3.281.
Step-by-step explanation:
Since both of the x terms are equal to y we can equate the x terms:-
-2x^2 = x - 2
2x^2 + x - 2 = 0
x = [-1 +/- √(1^2 - 4*2*-2) ] / 4
= ( - 1 +/- √(17)) / 4
= 0.781, -1.281.
When x = 0.781 y = 0.781 - 2 = -1.219.
when x = -1.281 , y = -1.281 - 2= -3.281.
301 minus 200? If so, that is 101
Well that's a 10cm radius and the formula for area of a circle is A= 3.14•R(squared). So to plug that in, that would be 3.14 • 10 squared or 3.14 • 100. 3.14•100=314