Question:
Sam is delivering two refrigerators that each weigh 105 kilograms. There is an
elevator with a weight limit of 1,000 pounds. Can he take both refrigerators on the
elevator in one trip? (1 kilogram 2.2 pounds)
Answer: yes he can
Step-by-step explanation:
Yes he can.
He can if the total weight of the 2 refrigerator didn't exceed the weight limit of the elevator.
Therefore:
Since 1 refrigerator weigh 105kg
2 refrigerator = 2 x 105kg = 210kg
The weight limit of the elevator 1000pounds convert to kg.
Since
2.2 pounds = 1kg
1000 pounds = 1000/2.2 kg
=454.55kg
Weight limit of the elevator = 454.55kg.
Since Weight of the 2 refrigerator is less than
weight limit of the elevator, he can take both refrigerators on the elevator in one trip
Answer:
50
Step-by-step explanation:
trust me bro
If they are parallel then the coefficients of x and y will remain the same. Only the constant will change.
2x + 3y = ?
2(-2) +3(3) = -4 + 9 = 5 so ? is 5
ANSWER: 2x + 3y = 5
Three times the 1st number plus the 2nd number plus twice the 3rd is 5 is the same as 3x+y+2z=5. If three times the 2nd number is subtracted from the sum of the 1st and three times the 3rd number, the result is 2 is just x+3z-3y=2. And if the 3rd number is subtracted from two times the 1st number and three times the 2nd, giving a result of 1 means 2x+3y-z=1. Then you use substition on these equations to get a equation where one variable equals 2 others, like using the first to get y=5-2z-3x and then this can be substituted into the other two to get x+3z-3(5-2z-3x)=2 and 2x+3(5-2z-3x)-z=1 we can then simplify and subtract the equations. After simplification we have 10x+9z=17 and 7z+7x=16 which can be turned into 70x+63z=119 and 70x+70z=160 which can be then subtracted to get that 7z=41 and z=41/7. Now we backtrack to a two variable equation like 7z+7x=16 and plug in to find x. So after plugging in we get 41+7x=16 and 7x=-25 so x=-25/7. Now we choose a 3 variable equation and plug in. So taking y=5-2z-3x we plug in 41/7 for z and -25/7 for x to get y=5-82/7+75/7 and y=5-7/7 and y=4. Therefore x = -25/7 y = 4 and z = 41/7.
Answer:
When you have an imaginary number in the denominator multiply the numerator and the denominator by the conjugate of the denominator.
