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Reil [10]
3 years ago
8

Solving Linear Equations: Variables on Both Sides I really need this please!

Mathematics
1 answer:
damaskus [11]3 years ago
4 0
Answer: x=-2/3

Explanation: Heres what my calculator says!
After you divide it will give you -2/3 :)

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I am so lost, please help
skelet666 [1.2K]

Answer:

u=\frac{9}{t}-\frac{1}{2} a t

Step-by-step explanation:

Step 1: Given equation: 9=\frac{1}{2} a t^{2}+u t

To get u, by subtraction equality property subtract both sides of the equation by  \frac{1}{2} a t^{2}.

\Rightarrow 9-\frac{1}{2} a t^{2}=\frac{1}{2} a t^{2}+u t-\frac{1}{2} a t^{2}  

\Rightarrow 9-\frac{1}{2} a t^{2}=u t  

Step 2: By division equality property, divide both sides of the equation by t.

\Rightarrow \frac{9-\frac{1}{2} a t^{2}}{t}=\frac{u t}{t}

$\Rightarrow \frac{9}{t}-\frac{1}{2} a t=u$  

Therefore, $u=\frac{9}{t}-\frac{1}{2} a t$.

So, in Emily’s physics class, she got $u=\frac{9}{t}-\frac{1}{2} a t$.

7 0
2 years ago
What is the constant of proportionality as a decimal? *
irakobra [83]

Answer:

qhttps://goo.gl/search/what+is+the+constant+of+proportionality

Identifying the Constant of Proportionality - Video & Lesson ... The constant of proportionality is the ratio between two directly proportional quantities. In our tomato example, that ratio is $3.00/2, which equals $1.50. Two quantities are directly proportional when they increase and decrease at the same rate.

7 0
3 years ago
Simplify 7n - 2n 3p 2p.
andrew11 [14]
7n^{-2}n^3p^2p=7n^{-2+3}p^{2+1}=\boxed{7np^3}
4 0
2 years ago
I need to know please help?
UkoKoshka [18]

The correct answer is B.

8 0
2 years ago
Read 2 more answers
The boundary of a lamina consists of the semicircles y = 1 − x2 and y = 16 − x2 together with the portions of the x-axis that jo
oksano4ka [1.4K]

Answer:

Required center of mass (\bar{x},\bar{y})=(\frac{2}{\pi},0)

Step-by-step explanation:

Given semcircles are,

y=\sqrt{1-x^2}, y=\sqrt{16-x^2} whose radious are 1 and 4 respectively.

To find center of mass, (\bar{x},\bar{y}), let density at any point is \rho and distance from the origin is r be such that,

\rho=\frac{k}{r} where k is a constant.

Mass of the lamina=m=\int\int_{D}\rho dA where A is the total region and D is curves.

then,

m=\int\int_{D}\rho dA=\int_{0}^{\pi}\int_{1}^{4}\frac{k}{r}rdrd\theta=k\int_{}^{}(4-1)d\theta=3\pi k

  • Now, x-coordinate of center of mass is \bar{y}=\frac{M_x}{m}. in polar coordinate y=r\sin\theta

\therefore M_x=\int_{0}^{\pi}\int_{1}^{4}x\rho(x,y)dA

=\int_{0}^{\pi}\int_{1}^{4}\frac{k}{r}(r)\sin\theta)rdrd\theta

=k\int_{0}^{\pi}\int_{1}^{4}r\sin\thetadrd\theta

=3k\int_{0}^{\pi}\sin\theta d\theta

=3k\big[-\cos\theta\big]_{0}^{\pi}

=3k\big[-\cos\pi+\cos 0\big]

=6k

Then, \bar{y}=\frac{M_x}{m}=\frac{2}{\pi}

  • y-coordinate of center of mass is \bar{x}=\frac{M_y}{m}. in polar coordinate x=r\cos\theta

\therefore M_y=\int_{0}^{\pi}\int_{1}^{4}x\rho(x,y)dA

=\int_{0}^{\pi}\int_{1}^{4}\frac{k}{r}(r)\cos\theta)rdrd\theta

=k\int_{0}^{\pi}\int_{1}^{4}r\cos\theta drd\theta

=3k\int_{0}^{\pi}\cos\theta d\theta

=3k\big[\sin\theta\big]_{0}^{\pi}

=3k\big[\sin\pi-\sin 0\big]

=0

Then, \bar{x}=\frac{M_y}{m}=0

Hence center of mass (\bar{x},\bar{y})=(\frac{2}{\pi},0)

3 0
3 years ago
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