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kicyunya [14]
3 years ago
15

For an intramural sports program at a particular college, the time to run one mile is recorded for 200 male students in the prog

ram. These times are approximately normal with mean 8 minutes and standard deviation 1 minute. For the same intramural sports program at the same college, the time to run one mile is recorded for 50 female students in the program. These times are approximately normal with mean 7.5 minutes and standard deviation 2 minutes. Devon participates in the intramural program for men. His best time to run the mile is 6.6 minutes. Kendall participates in the intramural program for women. Her best time to run the mile is 5.7 minutes. Who ran the mile faster relative to their gender?
Mathematics
1 answer:
jeka57 [31]3 years ago
5 0

Answer:

Devon has the lower z-score, so he was faster relative to his gender.

Step-by-step explanation:

Z - score

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Who ran the mile faster relative to their gender?

Who runs in less time the mile is faster, so whoever has the lower z-score is faster relative to their gender.

Devon participates in the intramural program for men. His best time to run the mile is 6.6 minutes.

For men, these times are approximately normal with mean 8 minutes and standard deviation 1 minute.

So we have to find Z when X = 6.6, \mu = 8, \sigma = 1

Z = \frac{X - \mu}{\sigma}

Z = \frac{6.6 - 8}{1}

Z = -1.4

Kendall participates in the intramural program for women. Her best time to run the mile is 5.7 minutes.

For women, these times are approximately normal with mean 7.5 minutes and standard deviation 2 minutes.

So we have to find Z when X = 5.7, \mu = 7.5, \sigma = 2

Z = \frac{X - \mu}{\sigma}

Z = \frac{5.7 - 7.5}{2}

Z = -0.9

Devon has the lower z-score, so he was faster relative to his gender.

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Answer:

Lets denote c the concatenation of strings. For a binary string <em>a</em> in B9, we define the element f(a) in E10 this way:

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Step-by-step explanation:

To show that the function f defined above is a bijective function, we need to prove that f is well defined, injective and surjective.

f   is well defined:

To see this, we need to show that f sends elements fromo b9 to elements of E10. first note that f(a) has 1 more binary integer than a, thus, it has 10. if a has an even number of 1's, then f(a) also has an even number because a 0 was added. On the other hand, if a has an odd number of 1's, then f(a) has one more 1, as a consecuence it will have an even number of 1's. This shows that, independently of the case, f(a) is an element of E10. Thus, f is well defined.

f is injective (or one on one):

If a and b are 2 different binary strings, then f(a) and f(b) will also be different because the first 9 elements of f(a) form a and the first elements of f(b) form b, thus f(a) is different from f(b). This proves that f in injective.

f is surjective:

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This shows that f is well defined from B9 to E10, injective, and surjective, thus it is a bijection.

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The entire trip took 6.5 hours.

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