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Zolol [24]
3 years ago
14

A student who is training for a distance race jogged for thirty minutes and covered a distance of 7.5 km. What is the average sp

eed of the student?
Mathematics
1 answer:
Tju [1.3M]3 years ago
3 0

Answer:

<h2>Average speed is 15km/h</h2>

Step-by-step explanation:

Step one:

given data:

total distance =7.5km

time taken= 30 min= 0.5 hours

we know that the average speed is the average distance divided by time taken

Step two:

mathematically expressed as

speed=distance/time

substituting we have

speed=7.5/0.5

speed=15km/hour

Hence the average speed is 15km/h

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Find the smallest 4 digit number such that when divided by 35, 42 or 63 remainder is always 5
alex41 [277]

The smallest such number is 1055.

We want to find x such that

\begin{cases}x\equiv5\pmod{35}\\x\equiv5\pmod{42}\\x\equiv5\pmod{63}\end{cases}

The moduli are not coprime, so we expand the system as follows in preparation for using the Chinese remainder theorem.

x\equiv5\pmod{35}\implies\begin{cases}x\equiv5\equiv0\pmod5\\x\equiv5\pmod7\end{cases}

x\equiv5\pmod{42}\implies\begin{cases}x\equiv5\equiv1\pmod2\\x\equiv5\equiv2\pmod3\\x\equiv5\pmod7\end{cases}

x\equiv5\pmod{63}\implies\begin{cases}x\equiv5\equiv2\pmod 3\\x\equiv5\pmod7\end{cases}

Taking everything together, we end up with the system

\begin{cases}x\equiv1\pmod2\\x\equiv2\pmod3\\x\equiv0\pmod5\\x\equiv5\pmod7\end{cases}

Now the moduli are coprime and we can apply the CRT.

We start with

x=3\cdot5\cdot7+2\cdot5\cdot7+2\cdot3\cdot7+2\cdot3\cdot5

Then taken modulo 2, 3, 5, and 7, all but the first, second, third, or last (respectively) terms will vanish.

Taken modulo 2, we end up with

x\equiv3\cdot5\cdot7\equiv105\equiv1\pmod2

which means the first term is fine and doesn't require adjustment.

Taken modulo 3, we have

x\equiv2\cdot5\cdot7\equiv70\equiv1\pmod3

We want a remainder of 2, so we just need to multiply the second term by 2.

Taken modulo 5, we have

x\equiv2\cdot3\cdot7\equiv42\equiv2\pmod5

We want a remainder of 0, so we can just multiply this term by 0.

Taken modulo 7, we have

x\equiv2\cdot3\cdot5\equiv30\equiv2\pmod7

We want a remainder of 5, so we multiply by the inverse of 2 modulo 7, then by 5. Since 2\cdot4\equiv8\equiv1\pmod7, the inverse of 2 is 4.

So, we have to adjust x to

x=3\cdot5\cdot7+2^2\cdot5\cdot7+0+2^3\cdot3\cdot5^2=845

and from the CRT we find

x\equiv845\pmod2\cdot3\cdot5\cdot7\implies x\equiv5\pmod{210}

so that the general solution x=210n+5 for all integers n.

We want a 4 digit solution, so we want

210n+5\ge1000\implies210n\ge995\implies n\ge\dfrac{995}{210}\approx4.7\implies n=5

which gives x=210\cdot5+5=1055.

5 0
3 years ago
A group of friends go out to breakfast the total bill including tax is $33 with the tax on the meal is 7% and a 15% tip is left
RSB [31]
The answer is 25.74$ because 7% of the 33$ is 2.31$ and the tip which 15% is 4.95$ so if you subtract all that it come out to 25.74$
4 0
3 years ago
A real estate agent earns a 2% commission on each home that he sells. What is his commission if he sells a home worth $1,000,000
harina [27]
Commission=2% of sales made

=2/100*$1,000,000
=$20,000
5 0
3 years ago
This is a word problem where you have to create an equation and a solution to.
IrinaVladis [17]
You are asked to find the team score, so it is convenient to let a variable represent that value. Let's call it "s", for "score". The problem statement tells you
.. Michaela scored s/5 . . . . . one fifth of the team's points
.. Aleah scored s/10 . . . . . . . one tenth o the team's points
These scores together are (s/5 +s/10) and that amount is 42 points.
.. s/5 +s/10 = 42
.. s(2/10 +1/10) = 42 . . . . . factor out s
.. s(3/10) = 42 . . . . . . . . . . form the sum of the numbers in parentheses
.. s = 42*10/3 = 140 . . . . . multiply by the inverse of the coefficient of s

The team scored 140 points.

______
Michaela scored 140/5 = 28 points; Aleah scored 140/10 = 14 points.
3 0
3 years ago
Write the fraction 9/45 in simplest form.
nordsb [41]

Answer:

1/5

Step-by-step explanation:

Divide 45 by 9. = 5. = 1/5

7 0
3 years ago
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