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Setler [38]
2 years ago
8

Classify the statement as an example of classical probability, empirical probability, or subjective probability. In California's

Pick Three lottery, a person selects a 3-digit number. The probability of winning California's Pick Three lottery is .1/1000
Mathematics
1 answer:
Nat2105 [25]2 years ago
5 0

Using probability concepts, it is found that the probability is subjective.

--------------------------------------

  • A classical probability is given by <u>the number of desired outcomes divided by the number of total outcomes</u>, considering no prior results of the experiments.
  • An empirical probability is similar to the classical, considering prior results of experiments.
  • The subjective probability involves personal beliefs along the calculations.

In this problem:

  • There are 900 3-digit number, thus, the classical probability of winning is:

p = \frac{1}{900}

  • The given probability is not the classical, and also does not involve previous trials, so it is subjective.

A similar problem is given at brainly.com/question/16101256

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3 years ago
The following data gives the speeds (in mph), as measured by radar, of 10 cars traveling north on I-15. 76 72 80 68 76 74 71 78
____ [38]

Answer:

71.123 mph ≤ μ ≤ 77.277 mph

Step-by-step explanation:

Taking into account that the speed of all cars traveling on this highway have a normal distribution and we can only know the mean and the standard deviation of the sample, the confidence interval for the mean is calculated as:

m-t_{a/2,n-1}\frac{s}{\sqrt{n} } ≤ μ ≤ m+t_{a/2,n-1}\frac{s}{\sqrt{n} }

Where m is the mean of the sample, s is the standard deviation of the sample, n is the size of the sample, μ is the mean speed of all cars, and t_{a/2,n-1} is the number for t-student distribution where a/2 is the amount of area in one tail and n-1 are the degrees of freedom.

the mean and the standard deviation of the sample are equal to 74.2 and 5.3083 respectively, the size of the sample is 10, the distribution t- student has 9 degrees of freedom and the value of a is 10%.

So, if we replace m by 74.2, s by 5.3083, n by 10 and t_{0.05,9} by 1.8331, we get that the 90% confidence interval for the mean speed is:

74.2-(1.8331)\frac{5.3083}{\sqrt{10} } ≤ μ ≤ 74.2+(1.8331)\frac{5.3083}{\sqrt{10} }

74.2 - 3.077 ≤ μ ≤ 74.2 + 3.077

71.123 ≤ μ ≤ 77.277

8 0
3 years ago
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