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yanalaym [24]
3 years ago
7

Could a quadrilateral have 4 obtuse angles

Mathematics
1 answer:
Alex73 [517]3 years ago
6 0
No because all quadrilaterals must equal a total of 360 degrees. If you have four angles that are greater than 90 degrees the sum of all the interior angles is greater than 360 degrees therefore it cannot exist as a quadrilateral.
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Someone help me with these problems!
vichka [17]

Answer:

6x + 3

Step-by-step explanation:

'x' and '5x' are like terms. Combining them will simplify the expression.

x+3+5x\\\\x+5x+3\\\\\boxed{6x+3}

Hope this helps.

6 0
2 years ago
Write down the factors of 55. Is 55 a prime or composite number? Explain how you know.​
horsena [70]

Answer:

Composite.

Step-by-step explanation:

because Prime numbers can only be recived when mulipltiy the number and itself, like 3.

55 can be mulipled by 1 AND 11 to get 55

4 0
3 years ago
Read 2 more answers
Im sorry for so many questions but i need help badly.
vlada-n [284]
The ratio of the circumference to the diameter is defined as pi
pi=circumference/diameter
that is how they got pi
in this question it woul be 15.7/5 which would be 3.14,





c=2pir
a=pir^2

c=2pir=16pi
divide both sides by 2pi
r=8

a=pir^2
a=pi8^2
a=pi64
a=64pi in²
5 0
3 years ago
If A(-5,7), B(-4,-5), C(-1,-6) and D(4,5) are the vertices of a quadrilateral, find the area of the quadrilateral ABCD.
MrMuchimi
After plotting the quadrilateral in a Cartesian plane, you can see that it is not a particular quadrilateral. Hence, you need to divide it into two triangles. Let's take ABC and ADC.

The area of a triangle with vertices known is  given by the matrix
M = \left[\begin{array}{ccc} x_{1}&y_{1}&1\\x_{2}&y_{2}&1\\x_{3}&y_{3}&1\end{array}\right]

Area = 1/2· | det(M) |
        = 1/2· | x₁·y₂ - x₂·y₁ + x₂·y₃ - x₃·y₂ + x₃·y₁ - x₁·y₃ |
        = 1/2· | x₁·(y₂ - y₃) + x₂·(y₃ - y₁) + x₃·(y₁ - y₂) |

Therefore, the area of ABC will be:
A(ABC) = 1/2· | (-5)·(-5 - (-6)) + (-4)·(-6 - 7) + (-1)·(7 - (-5)) |
             = 1/2· | -5·(1) - 4·(-13) - 1·(12) |
             = 1/2 | 35 |
             = 35/2

Similarly, the area of ADC will be:
A(ABC) = 1/2· | (-5)·(5 - (-6)) + (4)·(-6 - 7) + (-1)·(7 - 5) |
             = 1/2· | -5·(11) + 4·(-13) - 1·(2) |
             = 1/2 | -109 |
<span>             = 109/2</span>

The total area of the quadrilateral will be the sum of the areas of the two triangles:

A(ABCD) = A(ABC) + A(ADC) 
               = 35/2 + 109/2
               = 72
8 0
3 years ago
I’ll give brainly pls help me ☹️!!!
Lera25 [3.4K]

Answer:

728000 mosquitoes

Step-by-step explanation:

In attachment

Please giv brainliest, thanks!

6 0
3 years ago
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