Question

Write an equation of the line passing through the point (2,8) that is perpendicular to the line 2x-3y=7

Answer 1

Answer:

y = (-3/2x) + (35/4)

Step-by-step explanation:

So the perpendicular line will have a slope that is the opposite reciprocal of the other line's slope. Solve for the original line's slope first:

2x - 3y = 7 --> -3y = -2x + 7 --> y = (2x/3) - (7/3)

So, the slope of the perpendicular line will be (-3/2x)

Solve for the y-intercept of the perpendicular like by using the linear equation and substituting in (2,8):

8 = (-3/(2*2)) + b --> (32/4) = -(3/4) + b --> b = (35/4)

So, y = (-3/2x) + (35/4)

Hope that helps! :D