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Mathematics

2 answers:

faltersainse [42]2 years ago

7 0

I’ll answer it if u answer my questions :)

alexandr1967 [171]2 years ago

7 0

6x^9y^9 is the correct answer. Please give brainliest!

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What is the solution of this system of linear equations? 3y = x + 6 y – x = 3

Greeley [361]

Hello :
<span>3y = x + 6 ...(1)
y – x = 3...(2)
by (2) : y = x+3...(*)
subsct in (1) :
3(x+3) = x+6
3x-x= -9+6
2x= -3
x=-3/2
subsct in (*) : y =-3/2 +3 =3/2</span>

3 0

3 years ago

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Please help me solve this in class rn

oksian1 [2.3K]

The grinch mountain was the answer

4 0

2 years ago

I need help 6x-2y=10 x-2y=-5 solve by elimination

dem82 [27]

<h3><u>Explanation</u></h3>

Given the system of equations.

$\begin{cases} 6x - 2y = 10 \\ x - 2y = - 5 \end{cases}$

Solve the system of equations by eliminating either x-term or y-term. We will eliminate the y-term as it is faster to solve the equation.

To eliminate the y-term, we have to multiply the negative in either the first or second equation so we can get rid of the y-term. I will multiply negative in the second equation.

$\begin{cases} 6x - 2y = 10 \\ - x + 2y = 5 \end{cases}$

There as we can get rid of the y-term by adding both equations.

$(6x - x) + ( - 2y + 2y) = 10 + 5 \\ 5x + 0 = 15 \\ 5x = 15 \\ x = \frac{15}{5} \longrightarrow \frac{ \cancel{15}}{ \cancel{5}} = \frac{3}{1} \\ x = 3$

Hence, the value of x is 3. But we are not finished yet because we need to find the value of y as well. Therefore, we substitute the value of x in any given equations. I will substitute the value of x in the second equation.

$x - 2y = - 5 \\ 3 - 2y = - 5 \\ 3 + 5 = 2y \\ 8 = 2y \\ \frac{8}{2} = y \\ y = \frac{8}{2} \longrightarrow \frac{ \cancel{8}}{ \cancel{2}} = \frac{4}{1} \\ y = 4$