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Sedaia [141]
3 years ago
10

What is 8640 minutes in a day

Mathematics
1 answer:
ryzh [129]3 years ago
3 0

Answer:

6 days

Step-by-step explanation:

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ALGEBRICAL EXPRESSIONS<br><br> ADD 4y<br><br> (3y²+5y-7) and 2(y³-4y²+5)​
tangare [24]

Answer:

<h3>(3y2+5y-7)+2(y3-4y2+5)</h3>

3y2+5y-7+2y3-8y2+10

3y2-8y2+5y-7+10

-5y2+5y+17

7 0
3 years ago
How many thousands are in 5,000 ones
Iteru [2.4K]
5 thousands in 5,000 ones.
3 0
3 years ago
Read 2 more answers
A rectangular garden is 25 feet long by 10 feet wide. You have enough mulch to cover 1000 square feet. You would like to extend
m_a_m_a [10]
<span> Add x to both lenght and width and you get 25+x and 10+x. Set up equation with new area </span>
<span>(25+X)(10+X)=1000 </span>
<span>solve using quadratic formula 

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

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5 0
3 years ago
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How long does it take you and students 2 and 3 to clean up a 12 ft. X 12 ft wall covered in graffiti? Besides the answer (be spe
Ostrovityanka [42]

Answer:

At a combined speed of 6 in/min, it takes us 24 mins to clean the wall

Step-by-step explanation:

Since the question did not provide the speed with which each student cleans, we can make assumptions. This is so that we can solve the question before us

Assuming student 1 cleans at a speed of 2 inches per minute, student 2 cleans at a speed of 2½ inches per minute & student 3 cleans at a speed of 1½ inches per minute.

Let's list the parameters we have:

Height of wall (h) = 12 ft, Speed (student 1) = 2 in/min, Speed (student 2) = 2½ in/min, Speed (student 3) = 1½ in/min

Speed of cleaning wall = Height of wall ÷ Time to clean wall

Time to clean wall (t) = Height of wall ÷ Speed of cleaning wall

since students 1, 2 and 3 are working together, we will add their speed together; v = (2 + 2½ + 1½) = 6 in/min

1 ft = 12 in

Time (t) = h ÷ v = (12 * 12) ÷ 6 = 144 ÷ 6

Time (t) = 24 mins

8 0
3 years ago
What is the conditional probability that exactly four heads appear when a fair coin is flipped five times given that the first f
Phantasy [73]

Presumably, the coin tosses are independent of one another, so

P(\text{exactly 4 heads}\mid\text{first flip is tails})=P(\text{exactly 4 heads})=\dfrac1{2^4}=\dfrac1{16}

But if the coin flips are not independent, then we can't really say anything about this probability without any more information about how the flips are related...

8 0
3 years ago
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