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Vika [28.1K]
3 years ago
9

How do I solve 3x-5>0 ? Can someone explain please​

Mathematics
2 answers:
neonofarm [45]3 years ago
8 0

Answer:

Find my Answer attached.

Step-by-step explanation:

natta225 [31]3 years ago
6 0

9514 1404 393

Answer:

   x > 5/3

Step-by-step explanation:

In general, inequalities are solved the same way that equations are: undo what is done to the variable. (Whatever you do to one side of the inequality, you must also do to the other side.)

If you were to evaluate this inequality for some value of x, you would ...

  • multiply by 3
  • subtract 5

When solving for x, you undo these operations in reverse order. You undo the "subtract 5" by doing "add 5" <em>to both sides</em> of the inequality:

  3x -5 +5 > 0 +5

  3x > 5

You undo the "multiply by 3" by doing "divide by 3" <em>to both sides</em> of the inequality:

  (3x)/3 > 5/3

  x > 5/3 . . . . . . . the solution

__

<em>Additional comment</em>

The only difference between solving an equation and solving an inequality is that <em>multiplication or division by a negative number reverses the comparison symbol</em>.

Consider -1 > -2. When this is multiplied by -1, it becomes 1 < 2, with the comparison reversed.

__

As you can see, as long as multiplication and division are with positive numbers, the actual comparison symbol doesn't matter:

  3x -5 > 0   ⇒   x > 5/3

  3x -5 = 0   ⇒   x = 5/3

  3x -5 < 0   ⇒   x < 5/3

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