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3 years ago

What is the equation, in slope-intercept form, of a line that passes through the points (1,8) and (-2,2)?

Mathematics

1 answer:

MAXImum [283]3 years ago

8 0

Answer:

y=2x+6

Step-by-step explanation:

You can first set up the equation in point slope form and plug in your two points to solve for slope

y-y=m(x-x)

8-2=m(1+2)

6=m(3)

m=2

Then plug in one point into the point slope form equation to make it into slope intercept form

y-8=2(x-1)

y=2x-2+8

y=2x+6

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Ling is using fraction strips to add 2/3 and 7/12's The sum is one whole Plus how many twelves?

Leno4ka [110]

Hello from MrBillDoesMath!

Answer:

3/12 (aka 1/4)

Discussion:

2/3 + 7/12 = 8/12 + 7/12 => as 2/3 = (2*4)/(3*4) = 8/12

= 15/12

= 1 + 3/12

Thank you,

MrB

5 0

4 years ago

Find the percent of increase from 40 gallons to 89 gallons. Round to the nearest tenth of a percent if necessary.

fredd [130]

Solution

- 89 gallons contains 40 gallons twice such that:

$89=40+40+9$

- This means that we can find at least 200% of 40 gallons in 89 gallons. This gives us what to expect.

- To get the percentage we are looking for, we should use the formula:

$\frac{\text{new}}{\text{old}}\times100\text{ \%}$

New, in this case, is 89 gallons, Old is 40 gallons.

- Thus, we can calculate the percentage as follows:

$\begin{gathered} \frac{89}{40}\times100 \\ =2.225\times100 \\ =222.5\text{ \%} \end{gathered}$

Thus, the answer is 222.5%

8 0

1 year ago

Write a equation for each line

musickatia [10]

Answer:

Line l: y=4

Line m: y=-2x+4

Line n: y=x-1

Line p: x=-4

Hope this helps!

5 0

3 years ago

Two boats leave port at noon. Boat 1 sails due east at 12 knots. Boat 2 sails due south at 8 knots. At 2 pm the wind diminishes

Ivan

Answer:

14.86 knots.

Step-by-step explanation:

<em>Given that:</em>

The boats leave the port at noon.

Speed of boat 1 = 12 knots due east

Speed of boat 2 = 8 knots due south

At 2 pm:

Distance traveled by boat 1 = 24 units due east

Distance traveled by boat 2 = 16 units due south

Now, speed of boat 1 changes to 9 knots:

At 3 pm:

Distance traveled by boat 1 = 24 + 9= 33 units due east

Distance traveled by boat 2 = 16+8 = 24 units due south

Now, speed of boat 1 changes to 8+7 = 15 knots

At 5 pm:

Distance traveled by boat 1 = 33 + 2 $\times$ 9= 51 units due east

Distance traveled by boat 2 = 24 + 2 $\times$ 15 = 54 units due south

Now, the situation of distance traveled can be seen by the attached right angled $\triangle AOB$ .

O is the port and A is the location of boat 1

B is the location of boat 2.

Using pythagorean theorem:

$\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}\\\Rightarrow AB^{2} = OA^{2} + OB^{2}\\\Rightarrow AB^{2} = 51^{2} + 54^{2}\\\Rightarrow AB^{2} = 2601+ 2916 = 5517\\\Rightarrow AB = 74.28\ units$

so, the total distance between the two boats is 74.28 units.

Change in distance per hour = $\dfrac{Total\ distance}{Total\ time}$

$\Rightarrow \dfrac{74.28}{5} = 14.86\ knots$

6 0

3 years ago

Suppose that the local sale tax rate is 4% and you purchase a car for $17,000.

lapo4ka [179]

A. $680 tax is paid
B. The total cost is $17,680

4 0

3 years ago