All categories

2 years ago

What is 5 + x=6.? Mm

Mathematics

2 answers:

elena55 [62]2 years ago

8 0

Answer:

5 + x = 6

X = 6 -5

X = 1

Value of X is 1

Papessa [141]2 years ago

6 0

Answer:

x = 1

Step-by-step explanation:

Work backwards:

5 + x = 6 (minus 5 from both sides)

6-5 = x

x =1

Sub in to check

You might be interested in

Quiana took out a loan to pay for a new car initially she owed the lender 15,234.68. she has repaid 247.43 of the loan each mont

Serga [27]

Given Information:

Initial amount of loan = $15,234.68

Monthly payment = $247.43

Number of months = 5

Required Information:

Net change in loan = ?

Answer:

Net change in loan = $1,237.15 = $1,237(3/20)

Step-by-step explanation:

Quiana owed her lender an amount of 15,234.68 initially, she repaid the lender each month with an amount of $247.43 for 5 months, so the total amount that she repaid is

Total amount repaid = Monthly payment*Number of months

Total amount repaid = $247.43 × 5

Total amount repaid = $1,237.15

The remaining owed amount is given by

Balance = Initial amount of loan - Total amount repaid

Balance = $15,234.68 - $1237.15

Balance = $13,997.53

So the net change to the loan from Quiana's perspective over the past 5 months is,

Net change in loan = Initial amount of loan - Balance

Net change in loan = $15,234.68 - $13,997.53

Net change in loan = $1,237.15

Net change in loan = $1,237(3/20)

Therefore, the net change to the loan from Quiana's perspective over the past 5 months is $1,237.15

6 0

3 years ago

For a party, three solid cheese balls with diameters of 2 inches, 4 inches, and 6 inches, respectively, were combined to form a

schepotkina [342]

Answer:

The radius of the new cheese ball formed is approximately 6.603 inches.

Step-by-step explanation:

We are given the following in the question:

Radius of three cheese ball = 2 inches, 4 inches, and 6 inches

They were combined to form a new cheese ball.

Thus, we can write

Volume of three cheese balls = Volume of new cheese ball.

Let r be the radius of new cheese ball.

Volume of sphere =

$\displaystyle\frac{4}{3}\pi r^3$

Putting values, we get:

$\displaystyle\frac{4}{3}\pi r_1^3 + \displaystyle\frac{4}{3}\pi r_2^3 +\displaystyle\frac{4}{3}\pi r_3^3 =\displaystyle\frac{4}{3}\pi r^3\\\\\frac{4}{3}\pi(2^3 + 4^3 + 6^3) = \displaystyle\frac{4}{3}\pi r^3\\\\2^3 + 4^3 + 6^3 = r^3\\\Rightarrow 288 = r^3\\\Rightarrow r = (288)^{\frac{1}{3}}\\\Rightarrow r \approx 6.603$