Answer:
Step-by-step explanation:
c
Answer:
no solution because they are the same
Step-by-step explanation:
Y = mx + b
1) m = slope of the tangent line = derivative at the point (pi/6, 1)
Function: y = 2sinx
Derivative: y ' = 2cosx
evaluate at x = pi/6=> y ' = 2cos(pi/6) = √3
2) equation using the slope and the point (pi/6, 1)
y - 1 = √3 ( x - pi/6 )
y = √3 x - √3(pi/6) +1 =√3 x + 0.093
y = √3 x + 0.093
m = √3, b = 0.093
Answer:
b)
Step-by-step explanation:
A is invertible if and only if det(A)≠0. Let's compute the determinant of A and find the values k for which it is nonzero.
Using Sarrus's rule, we obtain that

Note that the determinant is a quadratic equation on k, which can be factored as above.
Now the determinant is only zero if k=5 or k=2 (the zeroes of the quadratic polynomial). Therefore, if k≠2,5 the determinant is nonzero so A is invertible.