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murzikaleks [220]
3 years ago
5

The meaning of an inequality depends on the __________________of the inequality sign.

Mathematics
1 answer:
lutik1710 [3]3 years ago
4 0

Answer:

Denpeds on the left hand side of nagetive of the inequality sign

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The volumes of two cylindrical cans of the same shape vary directly as the cubes of their radii. If a can with a six-inch radius
Cerrena [4.2K]

Answer:

The second similar can with a radius of 24-inch radius will hold 12 gallons

Step-by-step explanation:

The given parameters are;

The volumes of the cylindrical can ∝ (The radius of the cans)³

The volume of first can, V₁ = 1¹/₂ pints

The radius of the first can, r₁ = 6-inch

The radius of the second can, r₂ = 24-inch

Therefore, we have;

V ∝ r³

V = k × r³

∴ 1¹/₂ pints ∝ (6 in.)³

1¹/₂ pints = 43.3125 in³

∴ 43.3125 in³ = k × 216 in.³

The constant of proportionality, k = 43.3125/216 = 0.2005208333

Therefore, we have for the second can, we have;

V₂ = k × r₂³ = 43.3125/216 × (24 in.)³ = 2772 in.³

The volume of the second can = 2772 in.³

1 in.³ = 0.004329 gallons

∴ 2772 in.³ = 2772 × 0.004329 gallons = 12 gallons

Therefore, the volume the second similar can with a 24-inch radius will hold = 12 gallons.

8 0
3 years ago
A man travels 20 km by car from Town P to Town Q at an average speed of x km/h. He finds that the time of the journey would be s
yuradex [85]

Answer:

x = 20.

Step-by-step explanation:

First, you should remember the relation:

Distance = Speed*Time.

First, we know that a man travels a distance of 20km at a speed of x km/h, in a time T.

We can write this as:

20km = (x km/h)*T

We know that the time is shortened by 12 minutes if the speed is increased by 5km/h

Rewriting these 12 minutes in hours (remember that 60min = 1 hour)

12 min = (12/60) hours = 0.2 hours

Then from this, he can travel the same distance of 20km in a time T minus 0.2 hours if the speed is increased by 5 km/h

We can write this as:

20km = (x + 5 km/h)*(T - 0.2 h)

Then we have a system of two equations, and we want to find the value of x:

20km = (x km/h)*T

20km = (x + 5 km/h)*(T - 0.2 h)

First, we should isolate the variable T in one of the equations, if we isolate it in the first one, we will get:

20km/(x km/h) = T

Replacing that in the other equation we get:

20km = (x + 5 km/h)*(T - 0.2 h)

20km = (x + 5 km/h)*( 20km/(x km/h) - 0.2 h)

Now we can solve this for x.

Removing the units (that we know that are correct) so the math is easier to read, we get:

20 = (x + 5)*(20/x - 0.2)

We only want to solve this for x.

20 = x*20/x - x*0.2 + 5*20/x - 5*0.2

20 = 20 - 0.2*x + 100/x - 1

subtracting 20 in both sides we get:

20 - 20 = 20 - 0.2*x + 100/x - 1 - 20

0 = -0.2*x + 100/x - 1

If we multiply both sides by x we get:

0 = -0.2*x^2 + 100 - x

-0.2*x^2 - x + 100 = 0

This is just a quadratic equation, we can solve it using the Bhaskara's equation, the solutions are:

x = \frac{-(-1) \pm \sqrt{(-1)^2 - 4*(-0.2)*100} }{2*-0.2}  = \frac{1 \pm 9 }{-0.4}

Then the two solutions are:

x = (1 + 9)/-0.4 = -25

x = (1 - 9)/-0.4 = 20

As x is used to represent a speed, the negative solution does not make sense, so we should use the positive one.

x = 20

then the average speed initially is 20 km/h

3 0
3 years ago
What is the measure of angle 1? Put the number only.
Katarina [22]

Answer:

angle 1 = 120 degree

Step-by-step explanation:

75 degree + 45 degree = angle 1 (sum of two opposite interior angles is equal to the exterior angle formed)

120 degree = angle 1

6 0
2 years ago
Read 2 more answers
Given the graph below and the equation y = 4x, determine which function has the greatest rate of growth?
Marizza181 [45]

Answer:

Step-by-step explanation:

A slope of 4 has a greater rate of growth than a graph with a slope of 1

4 0
3 years ago
You have inherited land that was purchased for $25,000 in 1970. The value of the land has appreciated by
Darina [25.2K]

Answer:

Future value of land = 25,000[1.04]³⁰

Future value of land = $81,084 (Approx.)

Step-by-step explanation:

Given:

Purchase cost of land in 1970 = $25,000

Application rate = 4% per year

Find:

Price of land in 2000

Computation:

Number of year = 2000 - 1970 = 30 year

Future value of land = [Purchase cost of land][1+Application rate]ⁿ

F = P[1+r]ⁿ

Future value of land = 25,000[1+4%]³⁰

Future value of land = 25,000[1+0.04]³⁰

Future value of land = 25,000[1.04]³⁰

Future value of land = 25,000[3.24339]

Future value of land = 81,084.75

Future value of land = $81,084 (Approx.)

5 0
3 years ago
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