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adell [148]
3 years ago
12

PLZ I NEED HELP NOW!!!!!!!

Mathematics
2 answers:
slava [35]3 years ago
8 0

Answer:

20 divided by 2 = 10

10 x 1/4 = 10/4 = 2 2/4 = 2 1/2

taurus [48]3 years ago
7 0

Answer:

D

Step-by-step explanation:

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This is what I got. Good luck!

7 0
3 years ago
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A Government company claims that an average light bulb lasts 270 days. A researcher randomly selects 18 bulbs for testing. The s
Fofino [41]

Answer:

31.92% probability that 18 randomly selected bulbs would have an average life of no more than 260 days

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

In this question, we have that:

\mu = 270, \sigma = 90, n = 18, s = \frac{90}{\sqrt{18}} = 21.2

What is the probability that 18 randomly selected bulbs would have an average life of no more than 260 days?

This is the pvalue of Z when X = 260. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{260 - 270}{21.2}

Z = -0.47

Z = -0.47 has a pvalue of 0.3192.

31.92% probability that 18 randomly selected bulbs would have an average life of no more than 260 days

5 0
3 years ago
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gtnhenbr [62]

Answer:

addition

Step-by-step explanation:

add 40+8 and you get 48 :P

8 0
4 years ago
Help please with this question.
alexandr1967 [171]

Answer:

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Step-by-step explanation:

when you do the math for both inequalities they are equal to each other, despite the fact that one has multiplication and the other has addition.

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Please help me understand and solve this​
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Step-by-step explanation:

just multiple them and you'll get the results and the results you got add them together

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