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bezimeni [28]
3 years ago
9

Someone help please this was due a week ago

Mathematics
2 answers:
Oksi-84 [34.3K]3 years ago
8 0
Yes , he or she is right .
katrin2010 [14]3 years ago
3 0
The answer is 120 inches
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Si f(x) es igual a raiz de x al cuadrado menos 16 determinar f(5),f(4),f(6),f(3)
Nadusha1986 [10]

Aplicando la función, los valores numéricos son :

f(5) = -11

f(4) = -12

f(6) = -10

f(3) = -13

La función es dada por:

f(x) = (\sqrt{x})^2 - 16  = x - 16

Para los valores numéricos, reemplazamos x, luego:

f(5) = 5 - 16 = -11

f(4) = 4 - 16 = -12

f(6) = 6 - 16 = -10

f(3) = 3 - 16 = -13

Un problema similar es dado en brainly.com/question/7037337

4 0
3 years ago
HELP FAST ALL OF MY POINTS TO BE GIVEN TO YOU
gogolik [260]

Answer:

C > 9

Step-by-step explanation:


3 0
3 years ago
(i)Find the area of the parallelogram with base 14 cm and height 15 cm.
gulaghasi [49]

Answer:

The area should be "210 cm to the second power"

7 0
4 years ago
Read 2 more answers
Jim and Dianna want to save for their child’s college expenses. They find an annuity that pays 6% annual interest, compounded mo
lana66690 [7]

Answer:

future value = $49163.8

so required amount will be $491200 nearest $100

Step-by-step explanation:

given data

annual interest rate = 6 %

annuity = $300 per month

time period = 10 years

to find out

how much money will they have for the college expenses

solution

we know that effective rate will be

effective rate = \frac{0.06}{12}

effective rate = 5 × 10^{-3}

number of payment = 12 × 10 = 120

so future value will be express as

future value = annuity × \frac{(1+r)^t-1}{r}   .........1

future value = 300 × \frac{(1+5*10^{-3})^{120}-1}{5*10^{-3}}

future value = 300 × 163.8793  

future value = $49163.8

so required amount will be $491200 nearest $100

7 0
3 years ago
Here is an easy puzzle:
galina1969 [7]
The answer is 
date
1                  2                 3          4             5                                         31
r1                r2               r3           r4          r5               .  .  .                  r31
1gm           2gms         3<span>gms     4gms    5gms        .   .  .                 31gms

r1+r2+ .... +r31= 31(31+1) /2=496gms  (31 rings)

he only made 5 rings

31 rings----------> 496 gms
5 rings ------------> ? = 5 x496  / 31=80 gms

</span><span> the weights of those 5 rings was 80 gms</span>
4 0
4 years ago
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