Answer:
1.6962 = 1.70 (2 dp)
0.4247 = 0.425 to 3 dp
0.007395 = 0.007 to 3 dp
0.007395 = 0.0074 to 4 dp
32549 = 32500 to 3 significant figures
32549 = 32550 to 4 significant figures
909520 = 910000 to 3 significant figures
909520 = 909500 to 4 significant figures
Step-by-step explanation:
1.6962 = 1.70 (2 dp)
0.4247 = 0.425 to 3 dp
0.007395 = 0.007 to 3 dp
0.007395 = 0.0074 to 4 dp
32549 = 32500 to 3 significant figures
32549 = 32550 to 4 significant figures
909520 = 910000 to 3 significant figures
909520 = 909500 to 4 significant figures
Answer: A= (3,-3) . B(4,1). C= (1,0)
Step-by-step explanation:
Here is your answer
Money saved on each successive day is-
$3, &5, $7....
Clearly it forms an AP,
where
a1= 3
common difference, d= 2
n=20
So,
using formula
Tn= a1+(n-1)d
T20= 3+(20-1)2
= 3+ 19×2
= 3+ 38
=41
So, money saved on August 20= $41
Sum of money saved upto August 20 =
n/2 (a1+T20)
= 20/2 (3+41)
= 10× 44
= $440
HOPE IT IS USEFUL
The answer is 67 point 18.
