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3 years ago

I need help please help me quick

Mathematics

1 answer:

sergejj [24]3 years ago

3 0

Count the squares in between each letter.

Point Q is 6 units from Point R

Point R is 7 units from Point T

Point T is 3 units from Point S

For the area, it is easiest to take the area of each of those shapes and then add them.

(3*7/2) + (6*7)

10.5 + 42 = 52.5 Square Units

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The Sum Of 3 Consecutive integers is 138, What Are The Integers?

puteri [66]

If the integers were all the same, then each one would be 1/3 of 138 = 46 .

They're not all the same, but they're consecutive, so you can find them easily.
Just start with your 3 copies of 46, take ' 1' away from one copy, and add it
to another one. You haven't changed their sum. You just made one of your
copies 1 less than 46, and you made another one of them 1 more than 46.
Now you have 45, 46, and 47, and that sure looks like an answer to me.
Isn't that easy ... you only had to use some brain instead of a lot of messy
algebra. That's what 'Brainly' might be all about, I guess.

3 0

3 years ago

Read 2 more answers

Can someone help <br> (THERE SHOULD BE A FILE)

Lesechka [4]

6)
2(9+10) = 38
2(5+6) = 22

P = 38+22=60 in

14)
9 x 10 = 90
6 x 5 = 30
A = 90+50 = 140 in^2

4 0

3 years ago

Read 2 more answers

What is the equation of a line parallel to y=1/2×+6 that passes through (-4,1)

IgorC [24]

keeping in mind that parallel lines have exactly the same slope, let's check for the slope of the equation above

$y = \stackrel{\stackrel{m}{\downarrow }}{\cfrac{1}{2}}x+6\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}$

so we're really looking for the equation of a line whose slope is 1/2 and passes through (-4 , 1)

$(\stackrel{x_1}{-4}~,~\stackrel{y_1}{1})\hspace{10em} \stackrel{slope}{m} ~=~ \cfrac{1}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{1}=\stackrel{m}{ \cfrac{1}{2}}(x-\stackrel{x_1}{(-4)}) \\\\\\ y-1=\cfrac{1}{2}(x+4)\implies y-1=\cfrac{1}{2}x+2\implies y=\cfrac{1}{2}x+3$

5 0

2 years ago

At noon, the minute and the hour hands of a clock overlap. In how long will they again overlap?

kati45 [8]

Answer:

Okay. At noon, the hour and minute hand overlap. First, let’s calculate the speed of the hands.

The minute hand rotates once around the clock every hour. It goes 360 degrees in 60 minutes, so it rotates 360/60 or 6 degrees per minute. The hour hand goes once around the clock every 12 hours. Because there are 60 minutes in an hour, it goes 360 degrees 12*60 or 720 minutes. This means it travels at a speed of 360/720 or 0.5 degrees per minute.

Once the clock starts, the minute hand goes ahead and rotates ahead of the hour hand. At 1:00, the minute hand is at 12, and the hour hand is ahead at 1. This is where we will start our calculations.

Now, we have a variable, m, which is the minutes that have passed since the clock started. So, our minute hand speed is 6m, and our hour hand speed is 0.5m. However, because the hour hand is at one, it is at 30 degrees. (360/12 * 1.) This means our equation is 6m = 0.5m+30.

Now, we calculate.

6m = 0.5m+30

5.5m = 30

m = 30/5.5

m = 5.45

So at 5.45 minutes, the minute hand is at the hour hand. However, because one hour has passed since we started, we have to add on one hour.

So, our final total is 1 hour 5 minutes and 27 seconds.

Step-by-step explanation:

4 0

3 years ago

In March 2007, Business Week reported that at the top 50 business schools, students studied an average of 14.6 hours. You wonder

Rasek [7]

Answer:

The hypotheses used in this situation

$H_0:\mu = 14.6$

$H_a:\mu \neq 14.6$

Step-by-step explanation:

We are given that Business Week reported that at the top 50 business schools, students studied an average of 14.6 hours.

Mean = $\mu = 14.6$

Claim : The amount UMSL students study is different from this 14.6 hour benchmark.

The hypotheses used in this situation

$H_0:\mu = 14.6$

$H_a:\mu \neq 14.6$

5 0

3 years ago