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olasank [31]
3 years ago
9

The time required to complete a job varies inversely as the number of people working.

Mathematics
1 answer:
Crazy boy [7]3 years ago
5 0
48 for 6 electricians
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How do you write 70,000,000+400,000+10,000+8,000+500+30+9 in word form
alina1380 [7]
Seventy Thousand plus Four Hundred Thousand plus Ten Thousand plus Eight Thousand plus Five Hundred plus Thirty plus Nine.
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A circle has its center at the center of a square with 3-inch sides. Find the area of the square not covered by the circle Round
Aleonysh [2.5K]
So in order for us to know the area of the square that is not covered by the circle, we need to find first both the areas of the square and the circle.
So for the area of the square it is A = sxs. And for the circle is A = pi*r^2.
Let us find the area of the square first given that the side is 3 inches.
So A = 3*3
    A = 9 square inches.
Next is the area of the circle. Since the center of the circle is the same with the center of the square, the radius would be 1.5.
SO, A = (3.14)(1.5)^2
       A = 2.25 (3.14)
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Next, we deduct the area of circle from area of square and the result would be 1.935 <span>in². So the answer for this would be option B.
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7 0
3 years ago
A mixture of alcohol and water contains a total of 50 ounces of liquid. There are 10 ounces of pure alcohol in the mixture. What
suter [353]
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What is the equation of the line that passes through point (4, 12) and has a y-intercept of —2?
zmey [24]

Answer:

<h2>y = 3.5x - 2</h2>

Step-by-step explanation:

The slope-intercept form of an equation of a line:

<h3>y = mx + b</h3>

m - slope

b - y-intercept

We have y-intercept b = -2. Substitute:

<h3>y = mx - 2</h3>

We have the point (4, 12) → x = 4, y = 12. Put them in the equation:

12 = 4m - 2         <em>add 2 to both sides</em>

14 = 4m       <em>divide both sides by 4</em>

14/4 = m → m = 3.5

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3 years ago
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<em>Please</em><em> </em><em>see</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em> </em><em>for</em><em> full</em><em> </em><em>solution</em>

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